Have you ever wondered why some elements easily lose electrons while others strongly attract them? This tendency of an atom to lose electrons and form positive ions (cations) is known as electropositivity. Electropositive elements generally have a large atomic size, low ionization energy, and weak attraction for valence electrons. Metals such as alkali and alkaline earth metals show high electropositivity, which is why they readily form ionic compounds.
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Electropositivity can be defined as the tendency of metals to have an atom donate electrons and form well-charged cations. This material is primarily composed of metallic elements, particularly alkaline metals and alkaline earth metals. It is very important to note that electropositivity is opposite to electronegativity, which is a measure of atomic metals having the tendency to receive electrons and form poorly charged anions.
Therefore, light-emitting substances have very low electronegativities and very high-energy electrons have very low electropositivity (electronegative elements usually have no metals have the tendency to lose electrons to form cations, and electropositive metals substances usually do not receive electrons. electrons to form anions). The highest electropositive elements usually form ionic salts with electronegative elements. For example, sodium is a highly electropositive metal that easily provides an electron to obtain a stable electron suspension. Chlorine, on the other hand, is a highly potent element that absorbs electrons to achieve a stable octet.
Electropositivity depends on:
Relationship with Electronegativity:
Periodic Trends:
Metallic Character:
Examples:
1. Alkali metals (Group 1)
Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs). These are the most electropositive elements.
2. Alkaline earth metals (Group 2)
Magnesium (Mg), Calcium (Ca), Strontium (Sr), Barium (Ba)
3. Other metals
Aluminium (Al), Zinc (Zn), Iron (Fe)
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Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself. It is a relative property and does not have a fixed unit; instead, it is expressed on different scales such as the Pauling scale. Atoms with small atomic size, high effective nuclear charge, and high ionization energy show high electronegativity. Non-metals, especially elements on the right side of the periodic table, are highly electronegative. Understanding electronegativity helps in predicting bond type, bond polarity, and chemical reactivity,
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Question 1: Which of the following elements is most electropositive?
A. Na
B. Mg
C. K
D. Cs
Solution:
Electropositivity increases down a group and towards the left in the periodic table.
Cesium (Cs) lies below K and Na in Group 1 and has:
Hence, the correct answer is option (D)
Question 2: Which factor mainly increases the electropositivity of an element?
A. High electronegativity
B. High ionization energy
C. Large atomic radius
D. High electron affinity
Solution:
A larger atomic radius means valence electrons are farther from the nucleus and are easily lost, increasing electropositivity.
Hence, the correct answer is option (C)
Question 3: The correct order of electropositivity is:
A. $\mathrm{Na}>\mathrm{K}>\mathrm{Cs}$
B. $\mathrm{Cs}>\mathrm{K}>\mathrm{Na}$
C. $\mathrm{K}>\mathrm{Cs}>\mathrm{Na}$
D. $\mathrm{Na}>\mathrm{Cs}>\mathrm{K}$
Solution:
In Group 1, electropositivity increases down the group due to increasing atomic size and decreasing ionization energy.
Hence, the correct answer is option (B)
Question 4: Which element is least electropositive?
A. Fluorine
B. Oxygen
C. Nitrogen
D. Chlorine
Solution:
Fluorine has:
Therefore, it has the least tendency to lose electrons, making it least electropositive.
Hence, the correct answer is option (A)
Question 5: Electropositivity is maximum for an element having:
A. High effective nuclear charge
B. High ionization energy
C. Low electronegativity
D. High electron affinity
Solution:
Electropositivity and electronegativity are opposite properties.
Lower electronegativity → easier electron loss → higher electropositivity.
Hence, the correct answer is option (C)
Frequently Asked Questions (FAQs)
Electropositivity can be defined as the tendency of an atom to donate electrons and form positively charged cations.Example, sodium is a highly electropositive element which readily gives up an electron to obtain a stable electronic configuration.
Fluorine (shown in red) is an electronegative (at least electropositive) element (EN = 4.0). Cesium and francium (shown in blue) are less electropositive (EN = 0.7).
- Cesium (Cs) has the highest electropositivity.
The electropositivity of an object depends on many factors, such as the metal element of the object, the distance between the nucleus and the valence shell, the active nuclear charge applied to the valence electrons, and the ionization potential of the object.
Metals like Na, Mg, K, Ca, Fe, Zn lose electrons and form positively charged ions.
Since fluorine is the most electronegative element in the entire periodic table. Therefore, it is the least electropositive element.