Second Order Reaction - Examples, Graph, Equation, FAQs

Second Order Reaction - Examples, Graph, Equation, FAQs

Edited By Team Careers360 | Updated on Jul 02, 2025 04:57 PM IST

Chemical reactions control our daily lives, from the environment to the synthesis of key pharmaceuticals. In this respect, chemical kinetics explains phenomena limited to two-body events where the reacting molecules are together in solution and give a product or the rate of reaction can be controlled by two reactants interacting simultaneously with each other. These concepts, however, in an integrated capacity, act as almost a lifeline toward the betterment of perception of ordinary processes and further developments, especially in medicine, environmental science, and materials engineering.

This Story also Contains
  1. Detailed Explanation
  2. Some Solved Questions
  3. Conclusion

This paper attempts an in-depth discussion of second- and nth-order chemical kinetics reactions. We investigate some of the questions like how these kinds of reactions take place, how they are mathematically formulated, their various methods for establishing the order, practical applications, et cetera. At the end of this discussion, you should be able to see how exactly these principles bear on our comprehension of reaction mechanisms or how they are applied across the sciences.

Detailed Explanation

Second and nth-order reactions are cases where the rate of a chemical reaction is dependent on more than one power of concentration of reactants; unlike first-order reactions where they are dependent upon the concentration of one reactant raised to the power of one.

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1: Second-order reaction

The case in which the rate is proportional to the product of two concentrations of two reactants or to the square of the concentration of a single reactant is called a second-order reaction. Mathematically, it represents a reaction with two reactants A and B, where the rate might be defined by the formula:

$\frac{d[A]}{d t}=-k[A][B]$

For a reaction with a single reactant A:

$\frac{d[A]}{d t}=-k[A]^2$

One reason that second-order reactions are less common than first-order reactions is that often it requires two reactants to collide in a specific orientation for the reaction to occur. Thus, second-order reactions are less common than first-order reactions, but still very important in a great many chemical processes.

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2: nth Order Reaction

n-th order reactions The concept of second-order reactions can be generalized to any integer, with the index, once again, being the sum of exponents to which the concentrations appear in the rate law. For example, a third-order reaction with a single species A would be written:

$d t / d[A]=k[A] 3$

The nth-order reactions are variable and can occur in complex systems where more than one reactant or intermediate takes part to determine the overall rate of the reaction.

3: Methods of Determining Reaction Order

The experimental determination of the order of a chemical reaction is very important to learn about kinetics for designing appropriate conditions to get desired results. Following are some of the methods used:

- Initial Rate Method: The order of a reaction is often determined by measuring the initial rates of reaction varying the initial concentrations of reactants.

- Isolation Method: One may isolate some step or an intermediate of the sequence of reactions and study its influence on the overall rate.

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Integrated Rate Laws: These rate equations, derived directly from the experimental data, are integrated in order to learn about the order of a reaction and changes in concentration with time. a) Applications to Real Life and Academics:

Second and third-order reactions find applications in a wide range of scientific and industrial processes. In biological systems, enzymes often catalyze second or third-order reactions, influencing metabolic pathways and cellular functions. In industrial chemistry, understanding reaction order is essential for optimizing production and maintaining product quality. In academic research, driving the design of experiments and theoretical modeling improves our understanding of highly complex chemical systems.

Recommended topic video on (Second order reaction )


Some Solved Questions

1. Which of the following shows the expression of half-life period of second-order reaction?

$
\mathrm{A} \longrightarrow \mathrm{B}
$
(Where the initial concentration of $A$ is $[A]_0$ and the rate constant is $K$ )
1) $\frac{0.693}{\mathrm{~K}}$
2) $\frac{1}{\mathrm{~K}[\mathrm{~A}]_0}$
3) $\frac{[\mathrm{A}]_0}{2 \mathrm{~K}}$
4)none of above

Solution :
As we have learned,
Thus, $\mathbf{t}_{1 / 2}=\frac{1}{\mathrm{kA}_{\mathrm{o}}}$

Hence, the answer is the option (2)

2. Which of the following is the unit of rate constant for second-order reaction?

1) mol-1Ls-1

2)mol-2Ls-1

3)s-1

4)mol-1Ls-2

Solution

Unit for k dor second order = mol-1Ls-1

Hence, the answer is the option (1).


3. A second-order reaction requires 140 min to change the concentration of reactants from 0.16M to 0.02M The time required to become $0.08 \mathrm{M}=2 x$ min. What will be the value of x?

1)4 min

2)6 min

3)8 min

4) (correct)10 min

Solution

For second-order reaction

$\begin{aligned} & {[\mathrm{R}]_{\text {initial }}={ }^{\prime} \mathrm{a}^{\prime}=0.16 \mathrm{M}} \\ & {[\mathrm{R}]_{\text {final }}=0.02 \mathrm{M}}\end{aligned}$

$
\begin{aligned}
\mathrm{x} & =\mathrm{R}_{\text {initial }}-\mathrm{R}_{\text {final }} \\
& =0.16-0.02=0.14 \mathrm{M}
\end{aligned}
$


$
\begin{aligned}
& (a-x)=0.16-0.14=0.02 M \\
& K_2=\frac{1}{t} \times \frac{x}{a(a-x)}
\end{aligned}
$


$
\mathrm{k}_2=\frac{1}{140} \times \frac{0.14}{0.16 \times 0.02} \quad-(1)
$
Now, the time required to become a concentration

$\begin{aligned} & =0.08 \mathrm{M} \text { ie } \mathrm{x}=0.08 \mathrm{M} \\ & \mathrm{k}_2=\frac{1}{\mathrm{t}} \times \frac{0.08}{0.16 \times(0.16-0.08)}\end{aligned}$

Now put the value of $\mathrm{ k_{2}}$ form (1) in (2), we get

$\begin{aligned} & \frac{1}{140} \times \frac{0.14}{0.16 \times 0.02}=\frac{1}{t} \times \frac{0.08}{0.16 \times 0.08} \\ & t=20 \mathrm{~min}=2 \mathrm{x} \mathrm{min} . \\ & x=10 \mathrm{~min} .\end{aligned}$
.
Hence, the answer is the option (4).

Conclusion

In general, the second and nth-order reactions of the chemical kinetics explain how the concentration of reactants influences the rate at which a reaction occurs. The current paper has explored the mathematical fundamentals of the aforementioned entities, methods for determining their order, and other uses in other science fields. With the understanding of the principles at hand, prediction, and control of the chemical reactions for a specific will be at the scientist's disposal.

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NCERT Chemistry Notes :

Frequently Asked Questions (FAQs)

1. What characterizes a second-order reaction from the rest of the orders of a reaction?

Second-order reactions involve rates dependent upon the product of two reactant concentrations or the square of a single reactant concentration

2. Can nth-order reactions have non-integer reaction orders?

No, the term 'nth order reactions' refers to reactions where the rate is proportional to the product of powers of reactant concentrations -these powers have to be integers.

3. How does reaction order impact the overall rate of reaction?

Reaction order is the way that the concentration of reactants affects the rate of reaction and kinetic and efficient ways of chemical procedures.

4. What are some practical examples of second-order reactions in everyday life?

Examples include the reaction of two gas molecules, some enzymatic reactions, and some chemical reactions in solution.

5. Why should the order of a reaction be determined experimentally?

The experimental determination of the order of a reaction provides very crucial information for the proper design of reaction conditions and prediction of reaction behavior, especially in understanding the mechanisms.

6. What does the graph of concentration vs. time look like for a second-order reaction?
The graph of concentration vs. time for a second-order reaction is not a straight line like in first-order reactions. Instead, it is a curve that decreases more rapidly at the beginning and then levels off as the reaction progresses, forming a hyperbolic shape.
7. How can you determine if a reaction is second-order from experimental data?
To determine if a reaction is second-order, you can plot 1/[A] vs. time, where [A] is the concentration of the reactant. If this plot yields a straight line, the reaction is second-order. Additionally, you can analyze the half-life of the reaction, which should double each time the initial concentration is halved for a second-order reaction.
8. What is the integrated rate law for a second-order reaction?
The integrated rate law for a second-order reaction is 1/[A] = kt + 1/[A]₀, where [A] is the concentration at time t, k is the rate constant, and [A]₀ is the initial concentration. This equation allows you to calculate the concentration at any given time during the reaction.
9. How does the half-life of a second-order reaction differ from that of a first-order reaction?
In a second-order reaction, the half-life depends on the initial concentration of the reactant, whereas in a first-order reaction, the half-life is constant regardless of the initial concentration. For a second-order reaction, the half-life is given by t₁/₂ = 1/(k[A]₀), where k is the rate constant and [A]₀ is the initial concentration.
10. Can you provide an example of a common second-order reaction?
A classic example of a second-order reaction is the hydrolysis of esters in basic solution, such as the saponification of ethyl acetate: CH₃COOC₂H₅ + OH⁻ → CH₃COO⁻ + C₂H₅OH. This reaction is second-order overall, first-order with respect to both the ester and the hydroxide ion.
11. What is a second-order reaction in chemical kinetics?
A second-order reaction is a type of chemical reaction where the rate of the reaction is proportional to the concentration of one reactant squared or the product of the concentrations of two different reactants. In other words, the overall order of the reaction is two.
12. How does the rate equation for a second-order reaction differ from a first-order reaction?
The rate equation for a second-order reaction involves the concentration of reactants raised to the power of two, while a first-order reaction involves the concentration raised to the power of one. For example, for a reaction A → B, a second-order rate equation would be rate = k[A]², while a first-order rate equation would be rate = k[A].
13. How does the concept of activation energy apply to second-order reactions?
Activation energy applies to second-order reactions in the same way it does to other reaction orders. It represents the minimum energy required for reactants to form products. In a second-order reaction, the rate constant (k) is related to the activation energy (Ea) through the Arrhenius equation: k = Ae^(-Ea/RT), where A is the pre-exponential factor, R is the gas constant, and T is the temperature.
14. How can catalysts affect a second-order reaction?
Catalysts can significantly impact second-order reactions by providing an alternative reaction pathway with lower activation energy. This increases the rate of the reaction without being consumed in the process. While catalysts can change the rate of a second-order reaction, they do not change the overall order of the reaction or its mechanism.
15. How does the concept of rate-determining step apply to second-order reactions?
In a multi-step reaction mechanism, the rate-determining step is the slowest step that controls the overall reaction rate. For a reaction to be second-order overall, the rate-determining step must be second-order. This could involve the collision of two molecules or the reaction of a single molecule in a way that depends on its concentration squared.
16. How does the half-life method help in distinguishing between first-order and second-order reactions?
The half-life method is useful for distinguishing between first-order and second-order reactions. In a first-order reaction, the half-life is constant regardless of initial concentration. In a second-order reaction, the half-life is inversely proportional to the initial concentration. By measuring half-lives at different initial concentrations, you can determine the reaction order.
17. What are some common misconceptions about second-order reactions?
Common misconceptions include: assuming all bimolecular reactions are second-order (they may not be), thinking the reaction order always equals the number of reactant molecules (it's determined experimentally), and believing that second-order reactions always involve two different reactants (they can involve one reactant to the second power).
18. How does the concept of pseudo-first-order reactions relate to second-order reactions?
A pseudo-first-order reaction occurs when a second-order reaction is carried out with one reactant in large excess. The concentration of the excess reactant remains essentially constant, simplifying the rate law to appear first-order. For example, the hydrolysis of esters in excess water follows pseudo-first-order kinetics despite being inherently second-order.
19. How does the rate of a second-order reaction change as the reaction progresses?
As a second-order reaction progresses, the rate decreases more rapidly than in a first-order reaction. This is because the rate depends on the square of the concentration (or the product of two concentrations). As reactants are consumed, the concentration(s) decrease, causing a more pronounced slowdown in the reaction rate over time.
20. What is the difference between the differential and integrated rate laws for a second-order reaction?
The differential rate law for a second-order reaction expresses the instantaneous rate of change of concentration with time, typically as -d[A]/dt = k[A]². The integrated rate law, 1/[A] = kt + 1/[A]₀, relates the concentration directly to time, allowing for the calculation of concentration at any given time during the reaction.
21. How does the presence of a catalyst affect the activation energy and rate constant of a second-order reaction?
A catalyst lowers the activation energy of a reaction without being consumed. For a second-order reaction, this results in an increase in the rate constant k, as described by the Arrhenius equation. The lower activation energy means that a higher proportion of molecular collisions have sufficient energy to react, increasing the reaction rate without changing the reaction order.
22. What is the difference between an overall second-order reaction and an elementary second-order reaction?
An overall second-order reaction is determined experimentally and may consist of multiple steps. An elementary second-order reaction occurs in a single step at the molecular level, involving the simultaneous collision of two molecules. Not all overall second-order reactions are elementary; they may have complex mechanisms with different elementary steps.
23. How does the concept of steady-state approximation apply to complex second-order reactions?
The steady-state approximation is used in complex reaction mechanisms where an intermediate forms and reacts quickly. In second-order reactions with multiple steps, this approximation assumes that the concentration of the intermediate remains constant, simplifying the kinetics analysis. This can help in deriving rate laws for complex second-order reactions.
24. What is the relationship between the rate of disappearance of reactants and the rate of appearance of products in a second-order reaction?
In a second-order reaction, the rate of disappearance of reactants is proportional to the square of their concentration(s). The rate of appearance of products is directly related to this, but may differ by a stoichiometric factor. For example, if 2A → B, the rate of appearance of B is half the rate of disappearance of A.
25. How does the concept of rate-determining step influence the observed order of a reaction?
The rate-determining step, being the slowest step in a reaction mechanism, often determines the observed order of the reaction. If the rate-determining step is second-order, the overall reaction will typically exhibit second-order kinetics, even if other faster steps in the mechanism are of different orders.
26. What is the significance of the pre-exponential factor A in the Arrhenius equation for second-order reactions?
The pre-exponential factor A in the Arrhenius equation (k = Ae^(-Ea/RT)) represents the frequency of collisions between reactant molecules in the correct orientation for a reaction to occur. For second-order reactions, A is particularly important as it relates to the probability of successful two-molecule collisions.
27. How can you use the method of isolation to study the kinetics of a complex second-order reaction?
The method of isolation involves using a large excess of all reactants except one, effectively making their concentrations constant. This simplifies the rate law, allowing you to determine the order with respect to the limiting reactant. By repeating this process for each reactant, you can piece together the full second-order rate law.
28. What is the difference between a second-order reaction and a reaction with two rate-determining steps?
A second-order reaction refers to the overall kinetics of the reaction, where the rate depends on the concentration of reactants raised to the second power. A reaction with two rate-determining steps implies a more complex mechanism where two slow steps contribute significantly to the overall rate. These concepts are not mutually exclusive; a reaction could be both second-order and have two rate-determining steps.
29. How does the principle of microscopic reversibility apply to second-order reactions?
The principle of microscopic reversibility states that the mechanism of a reverse reaction must precisely retrace the steps of the forward reaction. In a second-order reaction, this means that if the forward reaction involves the collision of two specific molecules, the reverse reaction must involve the same two molecules separating in exactly the reverse manner.
30. How does temperature affect the rate of a second-order reaction?
Temperature affects the rate of a second-order reaction similarly to other reaction orders. An increase in temperature generally leads to an increase in the reaction rate. This is because higher temperatures provide more kinetic energy to the reactant molecules, increasing the frequency and energy of collisions, which in turn increases the likelihood of successful reactions.
31. What is the difference between a second-order reaction with respect to one reactant and a second-order reaction with respect to two reactants?
A second-order reaction with respect to one reactant has a rate that depends on the square of the concentration of that single reactant (rate = k[A]²). A second-order reaction with respect to two reactants has a rate that depends on the product of the concentrations of two different reactants (rate = k[A][B]). Both types have an overall order of two, but they behave differently and have different rate laws.
32. What is the significance of the rate constant (k) in a second-order reaction?
The rate constant (k) in a second-order reaction represents the speed of the reaction independent of concentration. It has units of concentration⁻¹ time⁻¹ (e.g., M⁻¹s⁻¹). The value of k depends on factors such as temperature and the presence of catalysts, but not on concentration. A larger k value indicates a faster reaction.
33. What is the relationship between reaction order and molecularity in second-order reactions?
Reaction order and molecularity are not always the same for second-order reactions. The order is determined experimentally and refers to how the rate depends on concentration. Molecularity refers to the number of molecules that must collide for the reaction to occur. A second-order reaction can be bimolecular (involving two molecules) or unimolecular (involving one molecule that decomposes in a rate-determining step).
34. Can a reaction with a second-order rate law have elementary steps that are not second-order?
Yes, a reaction with an overall second-order rate law can have elementary steps that are not second-order. The overall order is determined by the rate-determining step. For example, a reaction might have a fast first-order step followed by a slow second-order step, resulting in an overall second-order rate law.
35. How does the method of initial rates apply to determining the order of a second-order reaction?
The method of initial rates involves measuring reaction rates at different initial concentrations. For a second-order reaction, doubling the concentration of a reactant will quadruple the initial rate. By comparing the ratios of concentration changes to rate changes, you can determine if the reaction is second-order with respect to each reactant.
36. What is the significance of the y-intercept in a 1/[A] vs. time plot for a second-order reaction?
In a 1/[A] vs. time plot for a second-order reaction, the y-intercept represents 1/[A]₀, where [A]₀ is the initial concentration of the reactant. This plot is used to confirm if a reaction is second-order and to determine the rate constant. The slope of this linear plot gives the rate constant k.
37. What role do collision theory and orientation factors play in second-order reactions?
Collision theory is particularly relevant to second-order reactions as they often involve the collision of two reactant molecules. The rate depends on the frequency of collisions, the energy of collisions (related to temperature), and the orientation of the molecules. Proper orientation is crucial for a successful reaction, especially in complex molecules.
38. How can you use the integrated rate law to predict the concentration of a reactant at any time in a second-order reaction?
The integrated rate law for a second-order reaction, 1/[A] = kt + 1/[A]₀, can be rearranged to solve for [A] at any time t: [A] = [A]₀ / (1 + kt[A]₀). By inputting the initial concentration [A]₀, the rate constant k, and the time t, you can calculate the concentration [A] at that specific time.
39. What is the significance of the slope in a 1/[A] vs. time plot for a second-order reaction?
In a 1/[A] vs. time plot for a second-order reaction, the slope of the line represents the rate constant k. This is a key feature of the graphical analysis of second-order reactions, allowing for easy determination of the rate constant from experimental data.
40. Can a reaction be second-order with respect to one reactant and first-order with respect to another?
Yes, a reaction can be second-order with respect to one reactant and first-order with respect to another. This would result in an overall third-order reaction. The rate law would be expressed as rate = k[A]²[B], where the reaction is second-order in A and first-order in B.
41. How does the concept of rate-limiting step apply to determining the order of a reaction?
The rate-limiting step, or slowest step in a multi-step reaction mechanism, often determines the overall order of the reaction. If the rate-limiting step is second-order, the overall reaction will likely exhibit second-order kinetics, even if other steps in the mechanism are of different orders.
42. What is the relationship between the rate constant k and the half-life t₁/₂ in a second-order reaction?
In a second-order reaction, the relationship between the rate constant k and the half-life t₁/₂ is given by the equation: t₁/₂ = 1/(k[A]₀), where [A]₀ is the initial concentration. This shows that the half-life is inversely proportional to both the rate constant and the initial concentration.
43. How can you use dimensional analysis to verify if a reaction is second-order?
Dimensional analysis can help verify if a reaction is second-order by examining the units of the rate constant k. For a second-order reaction, k should have units of concentration⁻¹ time⁻¹ (e.g., M⁻¹s⁻¹). If the units of k match this pattern when calculated from experimental data, it supports the reaction being second-order.
44. What is the significance of the reaction quotient Q in understanding the progress of a second-order reaction?
The reaction quotient Q helps track the progress of a second-order reaction by comparing the concentrations of products to reactants at any point during the reaction. As the reaction proceeds, Q approaches the equilibrium constant K. In a second-order reaction, the rate at which Q changes is related to the square of reactant concentrations.
45. How can you determine the units of the rate constant for a second-order reaction?
The units of the rate constant for a second-order reaction can be determined by analyzing the rate law. Since rate = k[A]² (or k[A][B]), and rate has units of concentration/time, k must have units of (concentration⁻¹)(time⁻¹) to balance the equation. Common units are M⁻¹s⁻¹ or L mol⁻¹s⁻¹.

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