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Hi there,

In stage 1 there are two section one is MAT mental ability test Second is SAT scholastic ability test in this section you need to do few questions related to language. Actual no of question is not fixed but be prepared for the language based question as it will surely be asked.

I hope this help

QA can be categorised into Arithmetic, Algebra, Geometry and Advanced Mathematics. Practise chapter by chapter and develop mental calculations. Like practise more of basic summation, subtraction, fractions and tables. Numbers, Percentage, Profit and Loss, Simple and Compound Interest, Ratio, Proportionality, Time-Distance, Time-Work, Mixtures, Averages, Partnership, Permutation and Combinations, Probability, Set Theory, Progression and Series, Line, Angles, Triangles, Quadrilaterals, Polygon, Circles, Ares, Volume, Height and Distance, Coordinate Geometry, Basic Trigonometry are few important topics.

Because this section involves mathematics and takes most of your time, your focus should be on solving the problems efficiently in the beginning. Even if it takes time, practise upto perfection. Practise as many questions as you can in the conventional way. As and when you get a grip on the subject, you can go for short cuts. Memorise tables, square roots, cube roots, conversion from percent to fraction, etc. Solve sample papers on Mathematics. In the beginning, do not worry about the time it takes. As you practise, you will get the hang of the subject and it will be easier for you

Hello aspirant
Neet cut off for physically handicapped and with SC/ St or OBC   category  is 40th percentage..
Neet cut off 2019 score for SC/ St/ OBC PH candidates category was 119 to 107 .
Now this was previous year's cut off. Cut off is determined by various factors such as number if candidates appeared and qualified, difficulty level of exam, previous year's cut off . Cutoff changes every year so you should score 50 to 75 marks more than this to get admission in a good College.
For more information you can refer following link
https://www.careers360.com/mbbs-companion

Hi,

Well even though some colleges take admission through central quota, in state quota also if they are sitting for taking students then the bond will be applicable to that college also just like any other college. And maybe through central quota they might have other bond requirements. Visit the participating institute webpage on MCC website to know about bond information of different universities and colleges.

I hope my answer helps.

All the best.

Hello there

Yes, admission in all the veterinary colleges is through neet examination, neet examination has been mandatory for medical courses like MBBS , BDS  , BVSC, BAMS etc.

So, yes veterinary  comes under neet, and if you want to get admission then you need to clear neet examination.

Thankyou

Hello,

The cut off is different for each IIT.But to be able to get seat in Computer Science Engineering in IITs your rank must be in top 100 so that you have decent chances of getting seat in IITs like IIT-Bombay, IIT-Delhi, IIT-Kharagpur etc.Coming to second part of your question BE is more of theoretical and B.tech involves practical application.It isn't subject specific to classify CSE under BE or B.tech.There are colleges which offers B.E CSE and there are colleges which offers B.tech CSE.

hi Thaneeru ,

I think you are enquiring about VITEEE conducted for admission in Vellore Institute of Technology. This exam is conducted online and is of 2 and a half hour. Its consists of 125 questions(each of 1 mark) and no negative marking. It consist of five section i.e. Maths of 40 marks/questions , Physics of 35 questions , Chemistry of 35 questions , English of 5 questions  and Aptitude of 10 questions .

For detailed syllabus check here

I hope this answer will help.
All the best for the future!!

Hello,

Air resistance is constant and same in both cases, so I am ignoring that.

So, we threw a ball with velocity 'u'.

According to formula: v=u+at, we get 0=u+ ( -10 ) ( t1 ) ---> u=10 (t1)

This is because,

  • the final velocity is zero, as at max height, it will stop and then come down.
  • 10 is the acceleration due to gravity, rounded off.
  • t1, as given is time of ascent.

For case 2, v= 0 + 10 (t2) ----> v=10 (t2).

Now , finding ratios by dividing the equations obtained.

t2/t1 = v/u.   This is the required answer.

In reality, t1=t2. But since values are not given in the question, we assume them to be different.

Hope this helps.

Thanks.


Hello,

For admission into 3 year B.B.A in HR at UPES Dehradun there no entrance exam . Admission process is of done on basis of Group Discussion, Personal Interview and Marks Scored in Class 12th.

Minimum Eligibility Criteria is -

  • 75% aggregate in all 5 subjects of class 12th
  • Should be born on or after October 01st, 1998.


Click at this link to know more - https://www.careers360.com/university/university-of-petroleum-and-energy-studies-dehradun

Hope this was helpful.

Hello Hima

Aiims Delhi is not a Deemed University. It is an Autonomous University,  It directly comes under Central Government of India. The institute is fully under the control of the Ministry of Health and Family Welfare of the Government of India.

From this Year AIIMS application form has been discontinued and there will be only one exam i.e NEET.

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