The resultant will be a vector. So it is a tail of force on top and end on the head of the horizontal force. It is clear that the two forces and the resultant will form an equilateral triangle. So the resultant will be 10 dyne force acting on a line that makes 60 degree downwards angle with the horizontal.

If two forces are placed on adjacent sides of a parallelogram, the angle between them would be 120 degrees.

Now using the law of parallelogram we get

R = √10^2 + 10^2 + 2 x 10 x 10 x cos 120

R = √ 100 (cos 120 = - 1/2)

R = 10

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Hey!There

First find torque due to force F1 about required point..And then torque due to force F2 about same point.Then take vector addition of these two torque..

Ask if any query..

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