the fictions force acting on a freely falling body of mass 20 kilogram with reference to a frame moving with a downward acceleration of 6 metre per second sq would be
Gaurav ;
According to D'Alembert , a fictional force or a pseudo force acts in a direction opposite to that of the motion of the free body. It amounts up as an amount of it's mass multiplied by it's acceleration.
So, in this case the mass of the freely falling body is 20 kg and the acceleration is 6m per sec² . So, the fictional force will be 20*6 = 120 N .
Hope you got your answer!
Answer laterwhen a body lighter than water is completely submerged in water, the buoyant force acting on it is found to be n times its weight. The specific gravity of material of the body is
Hello Sree Vardhan,
You may use the concepts of laws of floatation to solve this fluids problem.
Consider mass of the body =m
therefore weight of the body = mg
Now let σ be the density of the object and ρ is the density of the water and V is the volume of the object.
So weight = mg = Vσg
and buoyant force = Vρg
bf=n×weight= Vρg=n*Vσg= σ /ρ = 1/n.
( Specific gravity = density of object /density of water.)
Hence, answer is 1/n.
Hope this helps
Regards
if i have to choose a carrer among three options 1st is law 2nd is journalism and 3rd is acting so which will be the best option among these three options
Every career path comes with its own perks. With technology ever evolving and crime evolving too, law needs to be always guarded and you will never run of opportunities in Legal field if you are talented enough. Journalism is good as long as you do not limit yourself to paparazzi culture but evolve beyond that. Acting is a strange field. It has its opportunities. The celebrity news that we read is the tip of the ice berg. What goes unsaid is the no.of people who aspire to be actors and the no.of people who really become one. Not every one can pull of a Karthik Aryan stunt. This is no means trying to pull your spirits down but this is the fact.
Two forces each numerically equal to 10 dynes are acting as shown in the figure then tha resultant is :
The resultant will be a vector. So it is a tail of force on top and end on the head of the horizontal force. It is clear that the two forces and the resultant will form an equilateral triangle. So the resultant will be 10 dyne force acting on a line that makes 60 degree downwards angle with the horizontal.
If two forces are placed on adjacent sides of a parallelogram, the angle between them would be 120 degrees.
Now using the law of parallelogram we get
R = √10^2 + 10^2 + 2 x 10 x 10 x cos 120
R = √ 100 (cos 120 = - 1/2)
R = 10
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for a body of mass 50kg the velocity time graph is shown in fig. the force acting on the body is
Greetings!
Slope under (v-t) curve gives acceleration but since you haven't provided the diagram so if I assume
a = 0.5m/s
Then,Force = m a
=50 *0.5=25N.
thankyou
Good luck
two forces f1=2i-5j-6k and f2=-i+2j-k are acting on a boby at points (1,1,0) and (0,1,2) respectively. Find torque acting on body about point (-1,0,1)
Hey!There
First find torque due to force F1 about required point..And then torque due to force F2 about same point.Then take vector addition of these two torque..
Ask if any query..
