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for a body of mass 50kg the velocity time graph is shown in fig. the force acting on the body is
Student Expert
1st Oct, 2019
Hello there!
Greetings!
Slope under (v-t) curve gives acceleration but since you haven't provided the diagram so if I assume
a = 0.5m/s
Then,Force = m a
=50 *0.5=25N.
thankyou
Good luck
Greetings!
Slope under (v-t) curve gives acceleration but since you haven't provided the diagram so if I assume
a = 0.5m/s
Then,Force = m a
=50 *0.5=25N.
thankyou
Good luck
Answer later 1420 Views
two forces f1=2i-5j-6k and f2=-i+2j-k are acting on a boby at points (1,1,0) and (0,1,2) respectively. Find torque acting on body about point (-1,0,1)
Student Expert
28th Sep, 2019
Hey!There
First find torque due to force F1 about required point..And then torque due to force F2 about same point.Then take vector addition of these two torque..
Ask if any query..
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