Hey there,

Yes, admission to Diploma in Computer Engineering on the basis of Class 12 marks is possible in many colleges. Eligibility and admission criteria vary from one institute to another. Some colleges give admission directly based on Class 12 marks, while others may conduct counselling or consider entrance exam

Hello Dear Student,

You can get directly find, check, get more information here: https://www.careers360.com/university/osmania-university-hyderabad/courses/bcom-idpg

Hope it helps!

Hello Dear Student,

With a SITEEE score of 60/120 , getting Computer Engineering / CSE-related branches at SIT Pune is difficult because recent expected cutoffs for CSE have been around 93–95+ marks , while IT has been around 86–88+ marks .

For SIT Hyderabad , your chances are better. SIT

Hello Dear Student,

If your JEE Main CRL rank is 31,306 and your OBC-NCL rank is 8,770 , then getting Computer Science Engineering (CSE) in top NITs is unlikely, as OBC-NCL CSE cutoffs at most NITs and IIITs close much earlier.

However, you can still target:

• Newer IIITs for CSE

Hello Dear Student,

Given your profile ( 93 percentile in JEE Main, 96 percentile in Maths, 87.8% CBSE ), I would rank the options as:

1. Thapar Institute (ENC)

• Strongest overall balance of brand, placements, alumni network, and industry recognition.
• ENC gives you exposure to both electronics and computing/software.
• Much

Hello Dear Student,

You can access NCERT Exemplar Class 12 Solutions from the link below:

https://school.careers360.com/ncert/ncert-exemplar-class-12-solutions

This page provides subject-wise exemplar solutions for Mathematics, Physics, Chemistry, and Biology with chapter-wise explanations and practice questions.

Hello Dear Student,

Hello Dear Student,

Dear Student,

If you want to pursue a Computer Science course , you need to apply for a BTech, BCA, or BSc degree in your preferred college. You will require to submit an application form and take an entrance exam, depending on the institute's admission process.

You can check this