Hello student ,

Since both forces have equal magnitude F1 = F2 = F

Since its given that the resultant force is equal to magnitude of one of the two forces F(resultant)= F

Therefore

F(R) = sqrt of F1^2 + F2^2 + 2F1F2Cos(theeta)

Substituting values of F

F = sqrt

Hi Dipak, hope you are doing well,

Let the forces be F1 and F2
F1^2 + F2^2 = 90 N
(as the angle between them is 90° or right angle)
when angle is 60°
F1^2 + F2^2 + 2 * F1 * F2 *cos(60)=117 N
90 + F1 * F2=117

hi mohammed,

Firstly, don't be afraid of the exam. Ask some senior who are great in academics for advice. Don't as from seniors who themselves got barely passed in this subject.

Analyze previous year papers of engineering mechanics, see what is important and if something is similar in all the

Hello dear aspirant.

I know civil engineering is one of the toughest branch in engineering specially because of these subjects like mechanics , engineering drawing , strength of materials etc. If you are not understanding them properly then have patience and practice as much as you can take the help

Hello Aspirant,

These are the list of the best books according to their rankings by already test attempted people

• Bihar  Polytechnic Sanyukt Pravesh Pariksha BCECE 2018 Success Package
• by Arihant Publications
• Bihar  Polytechnic Combined Entrance Competitive Examination BCECE 2018
• by Arihant Publications
• Bihar Polytechnic Sanyukt Pravesh Pratiyogita Pariksha BCECE 2018

Dear Aspirant

According to last year allotment seat result for admission to B.V.Sc. & A.H. degree course under 15% AIQ (2nd and final round), the last SC student was with AIR 105835 for College of Veterinary And Science Lakkidi P.O Wayand Kerala which clears that you have good chances for