HEY THERE!

YOU'VE SCORED 137 IN JEE MAINS 2022 SESSION 1, BUT IT WOULD BE BETTER IF YOU COULD MENTION YOUR DATE AND SHIFT OF EXAM. WELL, CONSIDERING YOUR PAPER DIFFICULTY LEVEL AS MODERATE, YOU CAN EXPECT A PERCENTILE OF " 96.5 - 98 %ile".

• MOREOVER IT'S QUITE DIFFICULT TO MENTION EXACT RANK AT THIS SCORE BECAUSE THE RANK USUALLY DEPENDS ON SOME FACTORS LIKE

1. NO. OF STUDENTS APPEARING IN THE PARTICULAR SHIFT AND
2. THE DIFFICULTY LEVEL OF YOUR PAPER, ETC.

HOWEVER, BASED ON PREVIOUS YEAR TRENDS ON MARKS vs PERCENTILE vs RANK, YOU CAN EXPECT IT TO BE: " AIR 29K-30K".

AGAIN, BASED ON PREVIOUS YEAR CUTOFF, THIS CAN BE SAID THAT YOU CAN GET NIT ROURKELA (FOR HOME STATE QUOTA) IN NON TECH- BRANCHES. SOME OF THEM ARE MENTIONED :

• CIVIL ENGG. DEPT
• FOOD-PROCESSING ENGG.
• MINING
• BIOTECHNOLOGY
• METALLURGICAL AND MATERIALS

FOR MORE DETAILS YOU CAN GO THROUGH THE ARTICLE: https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela

WELL YOU CAN PREDICT YOUR COLLEGE HERE USING THE COLLEGE PREDICTOR LINK: https://engineering.careers360.com/jee-main-college-predictor

You have scored 146 out of 300 in the Joint Entrance Examination or JEE Main! I must congratulate you for this is a splendid score and is almost sure to put you in the top 5 or 10 percentile bracket, in which many general students get admission in good colleges.

I would like to tell you that with this score and your ST quota, it is almost sure that you will secure an admit in NIT Rourkela! You may also predict your chances and college using our College Predictor:

https://engineering.careers360.com/jee-main-college-predictor?utm_source=google-search&utm_medium=paid&utm_campaign=jee-main-clgpd&gclid=EAIaIQobChMIt_WUnJXX-AIVUJlmAh1m6gctEAAYASAAEgJT4vD_BwE

Hope I have answered your question. All the best!

Dear aspirant,

The total fees of B.tech course in most of the NITs is more or less same. The tuition fees of each and every NIT is same which is 62.5k per semester considering your family income is more than 5L per annum.

The total fees including the hostel and mess would be around 8.5L for both these colleges. It is quite possible may be a 20-40k difference may occur but it would be more or less same.

To get complete information about the fees you can check out the link given below-

https://www.careers360.com/university/national-institute-of-technology-rourkela/courses

Dear student,

As per your question NIT Rourkela vs NIT Raipur on the following basis:-

Academic and Faculty:- NIT Rourkela has comparatively better faculties, NIT Raipur is also improving very rapidly in this sector.

Placement :- Comparing overall branch package goes in the favour of NIT Rourkela again. But comparing th CSE and electrical field both are almost equal. Both have 90%+ placement ratio in CSE and related stream.

Alumni Network:- NIT Rourkela has a better alumni network as compared to NIT Raipur but it is improving here also.

Location:- Raipur is capital and therefore connectivity is good and it is preferable for companies to hire easily. Rourkela is also growing but here NIT Raipur has an edge.

The home state quota of JEE Main is that state from where you have completed your class XIIth. Since you are studying in Odisha and must have completed your class 12th from a school which is located in Odisha, thus you CAN avail the home state quota benefit for Odisha in the JoSAA counselling for NIT Rourkela.

Moreover, the OBC category does not depend on your location, thus you can also avail the OBC quota benefit.

Wishing you all the best.

Hello,

Last year a candidate belonging to general category with rank 20915 (home state) secured admission to Mechanical Engineering in National Institute of Technology, Rourkela. A with rank 16075 (Other state) belonging to general category secured admission to Mechanical Engineering in National Institute of Technology, Rourkela. Considering the previous year cut off you need to secure rank in between 15000-20000. To secure such rank you need to score 99 percentile or above and you should aim to score minimum 250-260 marks or above in JEE Main. Cut off is subjected to change it may increase of decrease depending on total number of candidates appeared, difficulty level of examination and total number of seats available etc. To check the previous year cut off use the link below

https://josaa.admissions.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

If you are preparing for JEE Main 2022 you may check our JEE Main Knockout package and enroll in it to get help with your preparation

https://learn.careers360.com/knockout-jee-main-april/

Hello aspirant,

Looking at the previous year JEE mains Cutoff trends and analytics, you will need a minimum marks of around 120-140 in JEE mains to get admission in NIT rourkela, as a SC Category Students, to be on the safer side. Fo general Category it's 150+ marks in JEE mains to get NIT Rourkela.

Further, please note that the above mentioned prediction is totally based on the previous year JEE mains Cutoff trends and it may vary as it bound to change every year, The JEE mains Cutoff depends on various factors like : Difficulty level of the paper, previous year Cutoff trends, Number of aspirants appearing, etc.

Further, to know more about the JEE mains cutoff you can follow the below mentioned link to know more about it : https://engineering.careers360.com/articles/jee-main-cutoff

I hope that this will help.

hello aspirant...

hope you are doing good.

it depends. but the answer will be yes. just because it is IIT people assume that it is better that NITs but NIT rourkela is better than some IITs as it is In the year 2020, NIRF has NIT Rourkela ranked 19 and IIT Bhubaneswar ranked 26. As a result, NIT Rourkela is ranked higher than IIT Bhubaneswar.

NIT Rourkela has improved infrastructure, overall development, exposure, and curriculum, and now that it is one of three NITs, there is even more to look forward to.

hence, NIT Rourkela is better than some IITs.

hope this information helps you...

All the best.

Hi

Assuming you from general category.

Your profile suggests that your home state is Odisha

Making  prediction is difficult as  cutoff  depends upon various factors like :-

-----------) number of students/ candidates  that appeared in the  jee main exam,

-----------) number of available seats,

-----------) jee main examination difficulty level.

-----------) the branch you want,

-----------) the category you belong etc.

But yes,

When we go through previous year trend then,

In 6th round of josaa counselling 2021

----------) Under home state, closing rank was :-

• NIT Rourkela  :- 59726  rank and it was for Ceramic Engineering and M.Tech Industrial Ceramic (5 Years, Bachelor and Master of Technology (Dual Degree))

And for such  rank , you need  at least around 94 .5 percentile in jee main

You can check the same at:-

JOSAA 2021:- https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

Or

For previous years cut offs of top colleges like NITs, IIITs , you can also refer our page at :-

NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits

• Jee main marks vs rank vs percentile :-:- https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

• JEE main rank:- predictor:-predictor:- https://engineering.careers360.com/jee-main-rank-predictor

• JEE main college predictor, to know the colleges you can get admission in:- https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you  further,

To give an idea of jee main 2022 qualifying cut off ,

Minimum percentile in jee main 2021 to qualify it to be eligible for jee advanced is given below :-

--------) general :-87.8992241 percentile

--------) EWS:- 66.2214845 percentile

--------) OBC-NCL :- 68.0234447 percentile

--------) SC :- 46.8825338 percentile

--------) ST:- 34.6728999 percentile

--------) PWD :- 0.0096375 percentile

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

To enhance your performance in jee main, you can go for jee main rank booster course for which link is given below:-

https://learn.careers360.com/jee-main-rank-booster/

Thankyou