Hi

Making  prediction is difficult as  cutoff  depends upon various factors like :-

-----------) number of students

-----------) number of available seats,

-----------)  examination difficulty level etc

But yes,

When we go through previous year trend then

>>>>>>>>> With your  64.30 percentile/ nta score in jee main

You have chances in following colleges  which are listed below :-

Smt. Indira Gandhi College of Engineering, Navi Mumbai

Sinhgad College of Engineering, Vadgaon (BK), Pune

Thakur College of Engineering and Technology, Kandivali, Mumba

Shree Ramchandra College of Engineering, Lonikand,Pune

And more

As per 2021  cut off available at:-

https://drive.google.com/file/d/1vIXXECait_7XRPf1MtSqwnynwgoeNuZ5/view?usp=drivesdk

Above prediction has been made  considering  past year cut off data but  closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you further,

Minimum percentile in jee main 2022 to qualify it to be eligible for jee advanced is given below :-

--------) general :- 88.4121383percentile

--------) EWS:-63.1114141percentile

--------) OBC-NCL :-67.0090297percentile

So , with your percentile you are not eligible for jee advanced

--------) SC :-43.0820954percentile

--------) ST:-26.7771328percentile

--------) PWD :- 0.0031029percentile

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

Regards

ADITYA KUMAR

HELLO MY DEAR ASPIRANT!!!                                                                                                                                                                                                                                               I SUGGEST YOU TO SUBMIT THE MAIL IN THEIR OFFICIAL PAGE REGARDING THE HELP SERVICE LINE OR MAIL...

THEY MAY ANSWER REGARDING YOU'RE QUERIES AS YOU'RE PROBLEMS ARE NOT IGNORABLE..

BEST OF LUCK MATE!!!

Hello Aspirant,

See till now the session1 has not been ended so kindly wait for it's ending because only after the completion of session 1, the answer keys and response sheets for each shift would be released by National Testing Agency.

Till now no official answer key and response sheet of each candidate has been released by National Testing Agency.

However unofficial answer keys have been released by various coaching institutions for all those shifts that have been completed till date, so you can check them out from the link given below :-

JEE Main Answer Key 2022 Unofficial (Out) - Download PDFs Here! (careers360.com)

I hope this information helps you.

Good Luck!!

Most certainly yes! See, the opening rank is the rank of the person who had the highest rank in that branch or the person who was the first one to get the admit an the basis of rank, now if you have a rank higher than that person, then you will be the branch opener!

However, the rank you told might be of the last year, and in CSAB, the change of ranks may be drastic on an year-over-year basis, so look out for that.

Hope I have answered your question. All the best!

Hello Aspirant,

Generally no correction charges are there for correcting any kind of online form.

But, if you're changing your domain subject (which I believe would be the subject you're seeking admission in) then NTA would charge you according to different course fees.

Suppose you have applied for a course which has lower fees and want to change to a course with a higher fees. NTA will accordingly utilise your earlier payment and ask you to pay the remaining amount.

Hope this helps!

Hello Aspirant,

See it is quite difficult to tell you an exact figure of your CRL rank because it keeps on changing every year depending upon various factors but yes we can help you with approximate figures on the basis of analysis of previous year's data.

So If we go through the analysis of Percentile Vs CRL rank for JEE-Main 2021 then according to the percentile mentioned by you in the question your CRL rank is expected to be in the range of 53196 - 59800 .

Note that the ranks which are predicted are only the expected ranks on the basis of previous year's data so your actual ranks might vary depending upon current factors.

Based on such rank you have some chances for CSE in DELHI TECHNOLOGICAL UNIVERSITY because the closing CRL rank in 2021 was around 50k in Round 4 of JAC counselling for Delhi candidates and for Outside Delhi candidates, it was around 8.5k for OBC category.

You can check out previous year's cut-off from the official website given below :-

DTU R4 cutoff.pdf (careers360.mobi)

Note that the above prediction is made on the basis of latest cut-offs available and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your marks, category, and state you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

On such percentile, if you are a General candidate then you have very less or almost no chances to qualify for JEE-Advance 2022 but still the cutoffs for this year have not released yet officially.

As the cut-offs are released along with the JEE-Main 2022 result so for now you can get an idea from JEE-Main 2021 qualifying cut-offs that are enlisted below :-

==>> Common Rank List (CRL) - 87.8992241-100.0000000 Percentile

==>> GEN-EWS - 66.2214845-87.8950071 Percentile

==>> Other Backward Classes (OBC-NCL) - 68.0234447-87.8950071 Percentile

==>> Scheduled Caste (SC) - 46.8825338-87.8950071 Percentile

==>> Scheduled Tribe (ST) - 34.6728999 87.8474721 Percentile

==>> PwD - 0.0096375-87.8273359 Percentile

Note that in above table it is not the actual cut-off for JEE-Main 2022 but previous year's cut-off.

You can check out previous year's cut-off trends from the link given below :-

https://engineering.careers360.com/articles/jee-main-cutoff

I hope this information helps you.

Good Luck!!

Hello Aspirant,

As announced by NTA the exam dates for CUET 2022 are 15.07.2022, 16.07.2022, 19.07.2022, 20.07.2022 and 04.08.2022, 05.08.2022, 06.08.2022, 07.08.2022, 08.08.2022 and 10.08.2022.

As of now only tentative dates have been announced and no time table has been published for specific exams on specific dates. You will get to know more about your own exam dates when the time table is released or when you'll get your admit card finally.

Meanwhile it is advised to keep visiting the NTA website(s) https://cuet.samarth.ac.in and http://nta.ac.in for further updates with regards to the Examination.

Hope this helps!

Hi

Admit card release date hasn't been announced yet but yes JEE main 2022 1st session admit card is expected to been released very soon. So for updates keep any eye on the official website at jeemain.nta.nic.in or alternately can get live updates on our page as well at :-

https://news.careers360.com/jee-main-admit-card-2022-june-session-1-nta-jee-mains-hall-ticket-release-date-time-link-website-jeemain-nta-nic-in-live-news

Once, the admit card gets released,

You can download your admit card following the given below step  : -

---------) visit jeemain.nta.nic.in

----------) click on download admit card

---------) now you need to enter your JEE Main  application number and then your date of birth

---------) then you will have to enter the security pin which will be there mentioned on the screen and then click on submit button

---------)  your admit card will appear and then save it.

Your JEE main admit card will mention details like :-

• * your name along with your photograph

• * your examination centre,

• *your examination centre address ,

• *exam date

• *reporting time to the examination centre,

• * instructions to be followed in exam and other details

For more details about admit card, go through the link provided below :-

https://engineering.careers360.com/articles/jee-main-admit-card

Now that,

Limited time is there for your admission, so you should be focusing on your preparation.

>>>> practising chapterwise questions.

>>>> then revising the chapters.

>>>>  solve at least previous 10 year question as concept behind the question often gets repeated in the examination so it will be of great help in your preparation.

>>>>  go through mock test papers as it will let you know your preparation level and and weak areas so that you can work on them and perform well in your examination.

To help you boost your performance in jee main, we have jee main rank booster for you for which link is given below:-

https://learn.careers360.com/jee-main-rank-booster/

Thankyou

No, that's where you are mistaken. You will be applying for the two sessions under the same registration number henceforth implying the fact that the same student is appearing for both the exams.

Again, in case if you had asked that what will happen to the ranks if two different students got the same marks, here are the tie-breakers that will help NTA analyse the respective profiles and give the ranks. The rules are as follows:

Candidates with the higher percentile score obtained in Mathematics will be given a better rank.

If the tie still remains unresolved the candidates with higher percentile score in Physics will be awarded a better rank.

If the tie still remains unresolved the candidates with the higher percentile score in Chemistry will be awarded a better rank.

In case the tie is still not resolved, then the candidates older in age to be preferred.