if R vector = P vector + Q vector and R = P +Q find angle between P vector and Q vector
Hey,
In order to find the magnitude of a vector the formula is,
R^2= P^2 + Q^2 + 2 PQ cos¢
Now given, R= P+ Q
Squaring both sides, R^2= P^2 + Q^2 + 2PQ
Equating both the reaction,
R^2= P^2 + Q^2 + 2 PQ cos¢ = R^2= P^2 + Q^2 + 2PQ
Simplifying, cos¢ = 1
= Cos 0° = 1
Therefore the angle is 0 degree.
Hope that helps.
Thank you.
Answer laterDerive an expression for optimum velocity of a car on a circular level road.
Hey,
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16. Assertion :Addition of HBr to propene gives 1-Bromopropane as the major product Reason : According to Markovnikov rule negative part of the addendum gets attached to that carbon atom which possesses lesser number of hydrogen atoms.
Dear Student,
This question is concept based please refer your NCERT textbook.You should always learn from your textbook first then you can search online for solutions if you have doubt better learn from YouTube channel or join coaching institutes.
Thanks
Two masses 6kg and 2kg are at(6,-7)and (2,10) respectively. What is the centre of mass of the system of these two masses
Here lets assume m1 = 6kg and the corresponding position vector be r1=6i-7j and for m2 = 2 kg and corresponding position vector r2=2i+10j.
Now CM = m1r1+m2r2/(m1+m2)=(20/7) i - (11/7) j
Thus the center of mass will be located in the coordinate (20/7,-11/7)
I hope this answer helps. All the very best for your future endeavors!
A particle executes SHM of amplitude A. At what positions of its displacement (X) will its,(1) velocity be zero and maximum and (2) acceleration be zero and maximum?.
Dear Student,
- In SHM, the velocity is maximum at the equilibrium position
- Velocity is zero at the extreme position
- Further if the velocity is maximum, the acceleration is zero, meaning that the acceleration is zero whenever the object is at the initial position or the displacement of the particle is zero
- Acceleration is maximum at the extreme position as the displacement is maximum at the extreme position
The work done by a force is given by the area of a. Time -displacement graph b. Force -acceleration graph c. Velocity -time graph
Dear Student,
- Work is defined as the product of work and displacement.
- Hence, the work done by force is found by finding the area under the force displacement graph.
The maximum speed of a car on a level circular road of radius of curvature R, without skidding will be a. Independent of coefficient of friction b. Independent of mass c. Independent of R d.independent of g
Given, Radius of Curvature = R
Let, Static Friction = U
Now the centripetal force is providing the friction between the tyre and the road i.e.,
mv^2/R = Umg
=> v = (URg)^1/2
- Thus the Maximum speed will be independent of Mass.
I hope this answer helps. All the very best for your future endeavors!
Show that for small oscillations the motion of the simple pendulum is simple harmonic .Derive an expression for its time period. Does it depend on the mass of the bob. What is stokes law?. Derive an expression for the terminal velocity of a sphere falling through a viscous fluid.
Hello candidate,
For small oscillations, of a pendulum the angle taken between the two bobs were taken to be sin (theta), but we take the value of sin theta equal to theta. So, the expression for the time period of small oscillations is equal to 2π× √(length of the pendulum/ gravity) which is independent of the masses of the Bob attached.
Hope that this information was helpful for you!!
Describe various modes of vibration of air column in a closed pipe. Show that a closed pipe can produce only odd harmonics (b). What are beats ?.Discuss the formation of Beats graphically.
The various modes of vibration of air column are:
The air at the closed end is not free to vibrate so a node is formed at the closed end. While the air at the open end is free to vibrate with maximum amplitude so an antinode is formed at this end.The simplist mode is this one and it iscalled the fundamental mode.
Hope it helps!!
