Answer laterCan someone provide a detailed solution to this problem? In a car race, car A beats car B by 45 km, car B beats car C by 50 km, and car A beats car C by 90 km. The distance (in km) over which the race has been conducted is 1. 475 2. 500 3. 450 4. 550
Hi Khushi,
Let us assume that the length of racetrack is x kms.
so, now when A covers x kms then, B covers (x-45)kms and C covers (x-90) kms.
And when B covers x kms,then C covers (x-50) kms.
We have concluded from the given question is that the ratio of speed of racers is same as the ratio of distance covered in a specific given time.
Therefor, Ratio of speed of B and C,
(Speed of B) / (speed of C) = (x - 45) / (x-90) = x / (x-50)
=> x / (x-50) = 45/40
After solving this, we get x = 450 kms.
Hope it helps to clear your dilemma, thankyou!
I am weak at quantative ability so what should I do to overcome that and crack the exam
Hello,
The best way to master quantitative ability problems is to practice more and more problems.You have to try solving previous question papers of the exam that you are preparing for and then you will get an idea about the kind of problems asked.There might be questions that are repeatedly asked.Also attempt mock tests and sample papers.There are a lot of practice problems available online ,make use of that as well.
Hope this helps!!
Alok spends 20% of his mnthly incm on rent,25% on food and half of the remaining on other heads.He saves 2,750 per mnth.Find his mnthly incm.
Hello,
Let the income be x
So, from first and second condition, the total saving is,
x - ( 20% + 25% )of x = x - 0.45x = 0.55x
Now, Half of the remaining amount is spend and half is saved.
So, 0.275x is saved and 0.275x is spend.
So, now, as per last condition, 2,750/- is saved.
So, 0.275x = 2750
So, x = 10,000/-
Hence, his monthly income is 10,000/-
Best Wishes.
Sum of 30 integers is 150. Out of them 20 integers dont exceed 5, then what is the maximum possible average of those 20 integers ?
Hello Nitesh, Hope you are doing good and preparing hard for the exams you are preparing for. Coming Back to your questions the answer to this question is simple but logic needs to be applied here.
Here the question says sum of 30 integers is 150. Here average is means 150/30 i.e. 5.
Out of these 20 integers don't exceed 5. Let's take case where we imagine all numbers of these that is 20 numbers to be 5 . Since we have to maximise the average of these 20 numbers that's why we are taking 5. So total of these 20 numbers would be 20*5 i.e. 100 giving us the average to be 5.
Now the rest 10 numbers can be also taken as 5 giving sum of 50 fulfilling our required sum. So it shows that the average is same as we got from the 30 numbers in total.
So we got the answer that the maximum of those 20 numbers average can be 5.
Hope you understood the solution and wish you all the best for your preparation.
