Hello Aspirant,

What you should do is make sure that you enter the correct and valid AADHAR number and if it is correct and valid but still the issue persists then kindly turn off the tab and then re-open it and again try to register after sometime because sometimes server does not take new responses because of some technical glitches or heavy traffic.

******** But make sure to apply before March 31st 2022 as it is the last date to apply for JEE-Main 2022.********

You can apply from the link given below for JEE-Main 2022 :-

https://examinationservices.nic.in/jeemain22/root/Home.aspx?enc=Ei4cajBkK1gZSfgr53ImFVj34FesvYg1WX45sPjGXBr4k3BRYopUWpW/JMEseWKI

For latest updates and complete details about JEE-Main 2022 you can check out the link given below :-

https://engineering.careers360.com/exams/jee-main

To know about the complete process of filling up of JEE-Main 2022 application form kindly check out the link given below :-

https://engineering.careers360.com/articles/jee-main-application-form

You can also take JEE-Main Learning package for solving series of mock tests :-

https://learn.careers360.com/knockout-jee-main-april-one-month-subscription/?icn=jee-main-knockout&ici=c360-clevertap-sticky-articles-web

I hope this information helps you.

Good Luck!!

Hello Aspirant,

What you should do is make sure that you enter the correct an valid E-Mail ID and if it is correct and valid but still the issue persists then kindly turn off the tab and then re-open it and again try to register after sometime because sometimes server does not take new responses because of some technical glitches.

******** But make sure to apply before March 31st 2022 as it is the last date to apply for JEE-Main 2022.********

You can apply from the link given below for JEE-Main 2022 :-

https://examinationservices.nic.in/jeemain22/root/Home.aspx?enc=Ei4cajBkK1gZSfgr53ImFVj34FesvYg1WX45sPjGXBr4k3BRYopUWpW/JMEseWKI

For latest updates and complete details about JEE-Main 2022 you can check out the link given below :-

https://engineering.careers360.com/exams/jee-main

Application process for JEE-Main 2022 :-

>>>>> First of all you have to visit the application window of JEE-Main 2022 for which link is given above and then generate your application number and password.

>>>>> Now log-in using the application number and password generated in first step.

>>>>> There you will have to fill the application form with correct and valid details.

>>>>> Then after you will have to upload some documents and images in prescribed format which is given below :-

• The recent photograph should be either in colour or black & white with 80% face (without mask) visible including ears against a white background.
• Scanned photograph and signature should be in JPG/JPEG format (clearly legible).
• The size of the scanned photograph should be between 10 kb to 200 kb (clearly legible).
• The size of the scanned signature should be between 4 kb to 30 kb (clearly legible)
• The size of the scanned copy of the Category certificate (SC/ST/OBC/EWS etc.) should be in pdf between 50kb to 300kb (clearly legible).
• The size of the scanned copy of the PwD certificate should be in pdf between 50 kb to 300 kb (clearly legible).

>>>>> Now proceed for payment of JEE-Main 2022 application fee.

To know about the complete process of filling up of JEE-Main 2022 application form kindly check out the link given below :-

https://engineering.careers360.com/articles/jee-main-application-form

You can also take JEE-Main Learning package for solving series of mock tests :-

https://learn.careers360.com/knockout-jee-main-april-one-month-subscription/?icn=jee-main-knockout&ici=c360-clevertap-sticky-articles-web

I hope this information helps you.

Good Luck!!

Dear Student ,

First , you try to solve the question on your own , and then look into this solution :

Let us assume, present age of son is x ,

so present age of father will be 2x. ( as per the ques.)

20 years ago.

Age of son: (x-20)

Age of Father: (2x-20)

Now according to the question :

2x-20= 12(x-20)

x= 22

present age of father = 22*2= 44 years .

Hope this helps !

Hi aspirant,

See the number of times you can appear for JEE main examination does not depend upon whether you have appeared for previous year or not. Actually the rule says that a candidate can appear for JEE main for three consecutive years and JEE advanced for two consecutive years starting from the year he or she appears for the intermediate level examination. Since you have mentioned that you are a dropper that means you would be eligible to appear for JEE mean in 2022 you as well as 2023 but you can write JEE advanced examination only in 2022.

Hope it helps!!

Dear aspirant,

I am myself a jee qualifier and have taken admission into nit Jamshedpur. So, I followed a very simple strategy . I didn't follow much books specially for mathematics because I was strong it that but that might not be the case with you so

For mathematics:-

1- Allen handbook(for formulas)

2- Previous year jee problems and ncert exemplar.

For chemistry:-

1- Ncert chemistry

2- M.S Chauhan ( for organic)

For physics-

1- D.C Pandey series.

Hello There,

Hope you are doing Good.

Prime Minister's Special Scholarship Scheme (PMSSS) , generally provide scholarship to Jammu and Kashmir and Ladakh Students to encourage them for higher studies.

Eligibility for the PMSSS program - Candidate must have passed 10+2 or 12th from the board JKBOSE or CBSE located in Jammu and Kashmir and Ladakh.

As Per your question yes definitely you can get scholarship for B. optometry, this degree also considered among  Professional degre e. You can get more than one lakhs per year according to the course .

For more Information about Form filling and the documents required click on the given link below :- https://www.careers360.com/question-when-is-pmsss-jk-ug-documents-verification-starting-date-and-last-date

Hope this Information will help.

Thank you :)

Hello there,

See, a student can appear in JEE Mains entrance exam only two times in a year and also student can appear in JEE Mains in three consecutive year from the year of passing their class 12th exam.

NTA conducted the JEE Mains exam tentatively two times across various exam

centers.

After clearing this exam candidate will be eligible for getting admissions like NIT, IIIT, IIT , NITs etc.

Eligibility criteria for applying in this course :- Candidate who has passed the 12th class or its equivalent exam in the year 2020, 2021, or appearing in 2022 can apply for the entrance exam. Students can appear in the JEE Main exam for three consecutive year

Talking about the JEE Mains there is the no upper age limit for the exam .

for more Information about JEE Mains click on the given link below :- https://engineering.careers360.com/exams/jee-main

Hope this Information will help.

Thank you!

Hi aspirant,

See you can appear for JEE main examination in 3 consecutive years starting from the year you would appear for intermediate examination. That does not include the number of chances but only year. That means that if the examination is held in 4 sessions each year, then you can write the examination for 12 times but it would be limited to 6 if it happens twice a year.

Hope it helps!

Hello Aspirant,

It depends upon total number of attempts left with you. Like if you are going to pass your class 12th this year then you will have JEE-Main 2023 and 2024 and for JEE-Advance you will be left only with JEE-Advance 2023 provided that you also qualify JEE-Main 2023. This is because for JEE-Main maximum number of allowed attempts are 3 and for JEE-Advance it is 2 which includes 1 year as passing year of class 12th.

As you are preparing for JEE-Main 2022 so I am enlisting down some best books for your preparation which you can use for your preparation :-

@Physics

• Concepts of Physics-H. C. Verma
• Fundamentals of Physics-Halliday, Resnick and Walker
• Problems in General Physics-I. E. Irodov
• University Physics-Freedman and Young
• Understanding JEE physics series-DC Pandey
• Problem In Physics-SS Krotov

@Mathematics

• Higher Algebra-Hall and Knight
• Coordinate Geometry-S.L. Loney
• Differential and Integral Calculus-N. Piskunov
• Calculus and Analytic Geometry-Thomas and Finney
• IIT Mathematics for JEE Main & Advanced-M.L. Khanna
• Course in Mathematics for IIT-JEE-Tata McGraw Hill publication
• Problems Plus in IIT Mathematics-A Das Gupta
• Trigonometry-S L Loney

@Chemistry

• Modern Approach to Chemical Calculations-RC Mukherjee
• Organic Chemistry-Solomons and Fryhle
• Concise Inorganic-J. D. Lee
• Organic Chemistry-Morrison and Boyd
• University Chemistry-Freedman and Young
• Physical Chemistry-N Awasthi
• Arihant's Practice Book Chemistry for JEE Main And Advanced-R.K Gupta

You can also check out the JEE-Main knockout package for preparation of JEE-Main 2022 from the link given below :-

https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA

I hope this information helps you.

Good Luck!!