Dear Aspirant,

I have check the question it is misprint but I have tried to prove the Result hope this will help you.

here is the your answer:

recall your half-angle formula:

tan(x/2) = sinx/(1+cosx)

Now, we have

1+sec2A = (1+cos2A)/cos2A
= 1/[cos2A/(1+cos2A)]
= 1/[sin2A/(1+cos2A) * cos2A/sin2A]
= 1/(tanA cot2A)
= tan2A/tanA ---------------- (1)
Now we can see that
1+sec4A = tan4A/tan2A--------------------(2)

now we multiply eq.1 and 2, we get

(1+sec2A)(1+sec4A) = cot A*tanA

Hello!

Mains,Adv and other engineering entrance examinations are considered as one of the toughest examinations in our country. Moreover, these examinations will land you into one of the finest and premier Institutions of India. Hence, having a proper plan and following it perfectly will surely help you out in cracking these examinations. First of all, try to concentrate on concept learning. Being thorough with the concepts will help you out in solving conceptual questions easily and hence, improves your chance of getting selected. Then, try to give as many sample papers as you can. Go through the previous years question papers and solve each and every problem thoroughly. This will improve your accuracy as well as efficiency. Finally, stay confident and determined. Work smart and reach your goal.

Hope this Helps.

hello,

This question will get solved by applying rules and derivation. and you have to understand why it has happened like this. For that go to your maths teacher and ask him/her to help you out and explain you the steps he uses to solve it.

Some questions are important to understand as they might be get needed in understanding further concepts,answer questions and perform well with confidence.

Hope it helps!

Specifically, they are the inverses of the sine , cosine, tangent , cotangent, secant, and cosecant functions , and are used to obtain an angle from any of the angle's trigonometric ratios. Inverse trigonometric functions are widely used in engineering, navigation, physics, and geometry.

Integrating the derivative and fixing the value at one point gives an expression for the inverse trigonometric function as a definite integral.

Hii aspirants

let me clear your doubt.

There are vairous sites available online from where you can get previous year question paper of class 11 and 12 along with their answers also there are sites from which you can download ncert solutions. There are vairous apps also available for preparationof class 11 and12 and there wyou will get all the notes, question paper. etc.

I hope my answer will help you out

Good luck

Hello Danvarsha,

I hope you are doing good.

Preparing for JEE Mains, algebra and trigonometry are very important as they have a high weight age of marks in the exam.

Algebra - 35 Marks

Trigonometry - 7 Marks

Chapterwise Weightage in Algebra -

Complex Numbers & Quadratic Equations - 7 Marks

Permutations & Combinations - 3 Marks

Progressions & Series and Binomial Theorem - 9 Marks

Mathematical Reasoning & Induction - 3 Marks

Statistics - 3 Marks

Probability - 3 Marks

Matrices and determinants - 7 Marks

Chapterwise Weightage of Trigonometry -

Trigonometric Identities - 6 Marks

Solutions of Triangles & Heights and Distance - 1 Marks

I hope this information will help you. Good luck in the future!

Regards

Prashant Singh

Hello!

The answer is One.

Reason/Explanation-  here, expanding the given equation,

cos2x=2cos^2x-1

we get,

6cos^2x-4cos^2x+2-3=0

2cos^2x-1=0

cos^2x=1/2

cosx=1/(2)^(1/2)

x=45 degrees.

here,

tan^2x=(tan 45)^2=1

Therefore, Answer=1.

These kind of equations must be solved by simplifying it. Hope this helps!