The addition of cubes (of the two specified numbers) formula is called as the (a3+b3) formula. Without computing the two cubes, the sum can be calculated using the a cube plus b cube formula. The binomials of cubes are factorised using it as well.
The formula for "a cube + b cube" is written below:
The equation is (a + b)(a2- ab + b2)=a3+b3.
a cube plus b cube identity is another claim made for it.
By using the formula (a + b)3, we can determine that
(a + b)3 = a3+ b3 + 3ab(a+b)
We obtain (a + b) by subtracting 3ab (a + b) from both sides.
a3+ b3 = 3 - 3ab(a + b)
By taking (a + b) as common, we obtain
a3 + b3= [(a + b)2 – 3ab](a + b)
The above-mentioned statement can be written as follows:
(a + b) [a2 + b2 + 2ab - 3ab]=a3+b3 (By identity: (a plus b)2=a2+b2+2ab)
Hence, the formula for a3+b3 is -
a3+ b3 = (a + b) * (a2 – a*b + b2)
Example 1: Solve y3+27.
Answer: We can write y3+27 as y3 + 33
Currently, y3 + 33 is represented by c3+ d3.
c3+ d3 = (c+ d)* (c2 – cd + d2) yields the following results:
y3+ 33 = (y + 3) (y2 – 3y + 32)
y3+27.00 = (y + 3.00)* (y2 – 3y + 9.00)
Example 2: Prove that the c3+ d3 formula is valid for i3+(2j)3.
Answer: We know the formula -
c3+ d3 = (c+ d)* (c2 – cd + d2)
So here c=i and d = 2j
So when we will put the values in the equation, we will get-
i3+ (2j)3 = (i+ 2j)* (i2 – i*2j + (2j)2)
Here LHS is i3+ (2j)3
Solving RHS
= (i+ 2j)* (i2 – 2ij + 4j2)
= i3-2i2j+4ij2+2i2j-4ij2+8j3
=i3+8j3
It can be written as i3+ (2j)3.
Hence LHS=RHS
Therefore, The formula is valid for i3+(2j)3.
The cube of a binomial is calculated using the (a+b)3 formula. Some particular varieties of trinomials can also be factored in using this technique. This formula is included in the algebraic identities as well.
The equation for the cube of a two-term sum.
a3 + 3*a2*b + 3*a*b2 + b3=(a+b)3
One of the crucial algebraic identities is the (a+b)3 equation. A + B Whole Cube is how it should be read. The formula for (a+b)3 reads as follows a3 + 3*a2*b + 3*a*b2 + b3=(a+b)3
The (a-b)3formula, also known as the (a-b) the whole cube formula is used to calculate the cube of the difference between two terms. Some varieties of trinomials can also be factored using this technique. One of the crucial algebraic identities is the formula for the (a-b) entire cube. In most cases, the problems are quickly solved using the (a-b)3 formula without the need for laborious calculations.
a3 - 3 *a2*b + 3*a *b2 - b3 = (a - b)3
a minus b whole power 4-
a4 + b4 - 4a3 b + 6a2 b2- 4ab3=(a-b)4
The formula for "a cube + b cube" is written below:
The equation is (a + b)(a2- ab + b2)=a3+b3.
a cube plus b cube identity is another claim made for it.
By using the formula (a + b)3, we can determine that
(a + b)3 = a3+ b3 + 3ab(a+b)
We obtain (a + b) by subtracting 3ab (a + b) from both sides.
a3+ b3 = 3 - 3ab(a + b)
By taking (a + b) as common, we obtain
a3 + b3= [(a + b)2 – 3ab](a + b)
The above-mentioned statement can be written as follows:
(a + b) [a2 + b2 + 2ab - 3ab]=a3+b3 (By identity: (a plus b)2=a2+b2+2ab)
Hence, the formula for a3+b3 is -
a3+ b3 = (a + b) * (a2 – a*b + b2)
The (a-b)3formula, also known as the (a-b) the whole cube formula is used to calculate the cube of the difference between two terms. Some varieties of trinomials can also be factored in using this technique. One of the crucial algebraic identities is the formula for the (a-b) entire cube. In most cases, the problems are quickly solved using the (a-b)3 formula without the need for laborious calculations.
a3 - 3 *a2*b + 3*a *b2 - b3 = (a - b)3
One of the crucial algebraic identities is the (a+b)3 equation. A + B Whole Cube is how it should be read. The formula for (a+b)3 reads is as follows a3 + 3*a2*b + 3*a*b2 + b3=(a+b)3
a minus b whole power 4-
a4 + b4 - 4a3 b + 6a2 b2- 4ab3=(a-b)4
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