Imagine you’re trying to compare two routes on a map—one is a smooth highway, the other is a slightly bumpy village road. Even if you don’t measure every tiny bend or turn, you know the highway will usually take less time because it’s consistently better at every point. Inequalities in definite integration work exactly like this: when one function stays above another throughout an interval, its total “area under the curve” must also be greater. In this article, we’ll walk through how inequalities help us estimate integrals, compare areas, bound complex expressions, and simplify definite integration problems without solving them fully. We'll explore key inequality methods, practical examples, and exam-focused applications that make these ideas surprisingly easy to use.
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Definite integration is one of those ideas that looks abstract at first, but it’s basically a very systematic way of measuring “total change” or “accumulated value” over a fixed interval. Whether you’re tracking distance from speed, total cost from rate, or area under a curve, definite integrals are the mathematical tool that ties it all together.
When a function $f(x)$ is defined on a closed interval $[a,b]$, and $F(x)$ is another function such that
$,\frac{d}{dx}(F(x)) = f(x),$ for all $x$ in its domain, then the definite integral is given by:
$ \int_a^b f(x),dx = [F(x) + c]_a^b = F(b) - F(a) $
Here:
$a$ = lower limit
$b$ = upper limit
$F(x)$ = antiderivative of $f(x)$
This represents the net area between the curve $y = f(x)$ and the x-axis from $x = a$ to $x = b$.
Inequalities help compare expressions or functions when they’re not equal to each other.
Symbols used: $<, >, \le, \ge, \neq$.
In definite integration, inequalities become powerful tools to:
estimate the value of an integral
compare two integrals
apply average value theorems
use advanced inequalities like Jensen and Minkowski
Let’s walk through the major results.
When you're dealing with definite integrals, inequalities act like quick checkpoints—they help you estimate, compare, and bound the value of an integral without fully solving it. This section walks you through the most important inequality results that make definite integration easier.
If a function stays between two constants $m$ and $M$ on $[a,b]$, i.e.,
$m \le f(x) \le M$ for all $x \in [a,b]$, then
$ m(b - a) \le \int_a^b f(x),dx \le M(b - a) $
This is useful for estimating integrals without solving them exactly.
If $f(x)$ is continuous on $[a,b]$, then there exists some $c \in [a,b]$ such that:
$ f(c) = \frac{1}{b-a} \int_a^b f(x),dx $
This means the integral equals the area of a rectangle of width $(b-a)$ and height $f(c)$.
If $f(x) \ge g(x)$ for all $x \in [a,b]$, then:
$ \int_a^b f(x),dx \ge \int_a^b g(x),dx $
This is extremely common in inequality-based problems.
Let $\phi(x)$ be convex and $f(x)$ be integrated over $[a,b]$. Then:
$ \phi\left(\int_a^b f(x),dx\right) \le \int_a^b \phi(f(x)),dx $
This is widely used in optimization and probability theory.
For functions $f(x)$ and $g(x)$ in $L^p$ space:
$ \left( \int_a^b |f(x) + g(x)|^p,dx \right)^{1/p}
\le
\left( \int_a^b |f(x)|^p,dx \right)^{1/p}
+
\left( \int_a^b |g(x)|^p,dx \right)^{1/p} $
This forms the basis of many results in functional analysis and higher mathematics.
Example 1: Which of the following is a perfect way to write an integral?
1) $\int_1^3 f(x)$
2) $\int_5^8 f(x) d y$
3) $\int_7^9 f(x) d x$
4) $\int_7^5 f(x) d x$
Solution
As we have learnt,
Definite integration -
When $f(x)$ is integrated in a continuous limit, $(a, b)$: a, and b are known as the limit of integration.
wherein
Where a < x < b
In (A), dx is not written.
In (B), the variables are not the same.
In (D), the lower variable is greater than the upper variable.
Hence, the answer is the option 3.
Example 2: Which of the following is NOT a definite integral?
$
\int_{-5}^5 f(x) d x
$
2) $\int g(y) d y$
$
\int_3 \int_0^5 d u
$
4) $\int_5^6 0 d y$
Solution
As we have learned,
Definite integration -
When $f(x)$ is integrated in a continuous limit, $(a, b)$: a, and b are known as the limit of integration.
wherein
Where$a<x<b$
The upper and lower limits are not specified.
Hence, the answer is the option 2.
Example 3: Which of the following is NOT true?
(1) $\int_a^b f(x) d x=F(b)-F(a)$
$\int_0^0 f(x) d x=-F(a$
$\int_0^a f(x) d x=F(a)-F(b)$
4) $\int_a^a f(x) d x=0$
Solution
As we have learned,
lower and upper limit -
$\int_a^b f(x) d x=(F(x))_a^b$
$=F(b)-F(a)$
wherein
Where a is lower and b is the upper limit.
$\int_0^a f(x) d x=F(0)-F(a)$
and F(0) may or may not be equal to 0
Hence, the answer is the option (2).
Example 4: If $\int_a^b f(x) d x=F(b)-F(a)$; then which of the following is NOT true?
1) "a" s the lower limit
2) "b" is the upper limit
3) $\int_a^b f(x) d x=\int_b^a f(x) d x$
4) If $F(b)=F(a) ; \int_a^b f(x) d x=0$
Solution
As we have learnt,
lower and upper limit -
$\begin{array}{r}\int_a^b f(x) d x=(F(x))_a^b \\ =F(b)-F(a)\end{array}$
wherein
Where a is the lower and b is the upper limit.
$\int_a^b f(x) d x \neq \int_h^a f(x) d x$
Hence, the answer is the option 3.
This section provides a comprehensive list of key topics related to the application of inequality in definite integration, offering a structured path for exploring foundational and advanced concepts.
This section contain links to essential NCERT resources for Chapter 7 - Integrals, including the chapter notes, solutions, and exemplar solutions for Class 12 Maths.
NCERT Class 12 Maths Notes for Chapter 7 - Integrals
NCERT Class 12 Maths Solutions for Chapter 7 - Integrals
NCERT Class 12 Maths Exemplar Solutions for Chapter 7 - Integrals
Below is a link to a dedicated MCQ resource, ideal for testing and sharpening your understanding of how inequalities can be applied to solve definite integration problems in competitive exams like JEE Main.
Application Of Inequality In Definite Integration- Practice Question MCQ
We have provided below the practice questions related to different concepts of integration to improve your understanding:
Frequently Asked Questions (FAQs)
The integral is non-negative, i.e.
$ \int_a^b f(x) dx \geq 0, $
reflecting the accumulated area under the curve is positive or zero.
It guarantees some value $c$ in $[a,b]$ such that
$ \int_a^b f(x) dx = f(c)(b - a), $
offering a bridge to estimate integrals by evaluating $f$ at a point, useful for bounding integrals.
By bounding the integrand with simpler functions, if $f(x)$ lies between $g(x)$ and $h(x)$, then:
$ \int_a^b g(x) dx \leq \int_a^b f(x) dx \leq \int_a^b h(x) dx. $
So, we can estimate the integral of $f$ by integrals of $g$ and $h$.
It states:
$ \left|\int_a^b f(x) dx\right| \leq \int_a^b |f(x)| dx. $
Meaning the absolute value of an integral is always less than or equal to the integral of the absolute value of the function.
If $m$ and $M$ are the minimum and maximum of $f(x)$ on $[a, b]$, then:
$ m(b - a) \leq \int_a^b f(x) dx \leq M(b - a). $