In our daily life, we often see situations where things change continuously. For example, when you drive a car, the speed may increase or decrease at every moment. To understand how fast the speed is changing or how a quantity is growing at a particular instant, we use concepts like limits and derivatives. In class 11 maths limits and derivatives, you will learn how to calculate these changes and apply formulas to solve problems. This chapter is important because it forms the base for many higher-level maths and physics topics. In this article, we will cover limits and derivatives class 11, including class 11 limits and derivatives formulas, limits and derivatives class 11 solutions, and the class 11 limits and derivatives miscellaneous exercise with simple explanations to help you practice and understand the concepts easily in mathematics.
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A limit describes the value that a function approaches as the input gets closer to a specific point. Even if the function is not defined at that point, the limit can still exist by observing the behavior near it.
Mathematically, the limit of a function $f(x)$ as $x$ approaches $a$ is written as:
$\lim_{x \to a} f(x) = L$
This means that as $x$ gets closer to $a$, the value of $f(x)$ approaches $L$.
Consider the function $f(x) = x^2$.
As $x$ approaches $0$, $f(x)$ approaches $0$.
So, $\lim_{x \to 0} x^2 = 0$.
As $x$ approaches $2$, $f(x)$ approaches $4$.
So, $\lim_{x \to 2} x^2 = 4$.
Thus, in general, if $x$ approaches $a$, then $f(x)$ approaches some value $l$:
$\lim_{x \to a} f(x) = l$
Even if the function does not exist at $x = a$, still the limit can exist at that point as the limit is concerned only about the points close to $x=a$ and not at $x=a$ itself.
The following properties are used frequently while solving problems in limits and derivatives class 11:
Limit of a constant
If $c$ is a constant, then $\lim_{x \to a} c = c$
The limit of a constant is the constant itself.
Limit of the identity function
$\lim_{x \to a} x = a$
As $x$ approaches $a$, the value of $x$ itself approaches $a$.
Sum of limits
$\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x)$
The limit of the sum is the sum of the limits.
Difference of limits
$\lim_{x \to a} [f(x) - g(x)] = \lim_{x \to a} f(x) - \lim_{x \to a} g(x)$
The limit of the difference is the difference of the limits.
Constant multiple of a limit
$\lim_{x \to a} [c \cdot f(x)] = c \cdot \lim_{x \to a} f(x)$
A constant factor can be pulled out of the limit.
Product of limits
$\lim_{x \to a} [f(x) \cdot g(x)] = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x)$
The limit of a product is the product of the limits.
Quotient of limits
If $\lim_{x \to a} g(x) \neq 0$, then
$\lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)}$
The limit of a quotient is the quotient of the limits.
Power of a limit
If $n$ is a positive integer,
$\lim_{x \to a} [f(x)]^n = [\lim_{x \to a} f(x)]^n$
The limit of a function raised to a power is the power of the limit.
Root of a limit
If $n$ is a positive integer and the limit is defined,
$\lim_{x \to a} \sqrt[n]{f(x)} = \sqrt[n]{\lim_{x \to a} f(x)}$
The limit of a root is the root of the limit.
Polynomial and rational functions
Limits of polynomial and rational functions can be evaluated by direct substitution if the function is defined at that point.
When learning limits and derivatives class 11, it’s important to know how a function behaves when the input gets close to a particular value from different directions. This is where left-hand limits and right-hand limits are used. They help us understand the behavior of functions as the variable approaches a point from either smaller or larger values.
The left-hand limit, written as $ \lim_{x \to a^{-}} f(x) $, describes how the function $f(x)$ behaves when $x$ gets closer to $a$ from values smaller than $a$. In other words, we are observing what happens to the function when $x$ approaches $a$ from the left side of the number line.
For example, if we write $ \lim_{x \to a^{-}} f(x) = LHL $, it means that as $x$ gets closer to $a$ from the left side, the value of $f(x)$ approaches $LHL$.
The right-hand limit, written as $ \lim_{x \to a^{+}} f(x) $, describes how the function $f(x)$ behaves when $x$ approaches $a$ from values greater than $a$. This helps us study the behavior of the function from the right side of $a$.
If we write $ \lim_{x \to a^{+}} f(x) = RHL $, it means that as $x$ gets closer to $a$ from the right side, the value of $f(x)$ approaches $RHL$.
Example – Let’s understand this with an example, often seen in class 11 maths limits and derivatives miscellaneous exercise.
Consider the function $ f(x) = \frac{|x|}{x} $. We want to find how this function behaves near $x = 0$ by calculating both the left-hand limit and the right-hand limit.
We calculate the left-hand limit as:
$ LHL = \lim_{x \to 0^{-}} \frac{|x|}{x} $
Since $x$ is slightly less than $0$, we can write $x = 0 - h$, where $h > 0$ and very small. Therefore,
$ = \lim_{h \to 0^{+}} \frac{|0 - h|}{0 - h} $
$ = \lim_{h \to 0^{+}} \frac{h}{-h} $
$ = -1 $
So, the left-hand limit at $x = 0$ is $-1$.
Now, we calculate the right-hand limit as:
$ RHL = \lim_{x \to 0^{+}} \frac{|x|}{x} $
Since $x$ is slightly greater than $0$, we write $x = 0 + h$, where $h > 0$ and very small:
$ = \lim_{h \to 0^{+}} \frac{|0 + h|}{0 + h} $
$ = \lim_{h \to 0^{+}} \frac{h}{h} $
$ = 1 $
So, the right-hand limit at $x = 0$ is $1$.
From the above example, we see that the left-hand limit is $-1$ and the right-hand limit is $1$. Since they are not equal, the limit at $x = 0$ does not exist.
In general, the limit of a function at $x = a$ exists only if the left-hand limit and right-hand limit are equal. That is, $ \lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) $.
Even if the function is not defined at $x = a$, the limit can still exist if the values from the left and right sides approach the same number. This concept is very useful in class 11 maths limits and derivatives, as it helps us analyze functions at points where they may not be defined but behave consistently near that point.
In real life, we often need to know how quickly something is changing. For example, if you are driving, you may want to know how fast your speed is increasing at a particular moment. This rate of change is what we find using derivatives in class 11 limits and derivatives. The derivative helps us understand how a function changes at any point and is widely used in science, engineering, and economics.
The derivative of a function gives the rate at which the function’s value changes as the input changes. Suppose a function $f$ is defined on an interval that contains a point $x_0$, and the following limit exists:
$ \lim_{\Delta x \to 0} \frac{f(x_0 + \Delta x) - f(x_0)}{\Delta x} $
Then, the function is said to be differentiable at $x_0$, and the derivative of $f$ at $x_0$ is written as $f^{\prime}(x_0)$ and is defined by:
$ f^{\prime}(x_0) = \lim_{\Delta x \to 0} \frac{\Delta y}{\Delta x} = \lim_{\Delta x \to 0} \frac{f(x_0 + \Delta x) - f(x_0)}{\Delta x} $
This means that the derivative measures how $y$ (which is $f(x)$) changes when $x$ is changed by a small amount $ \Delta x $.
For all values of $x$ where this limit exists, the derivative is written as:
$ f^{\prime}(x) = \lim_{\Delta x \to 0} \frac{\Delta y}{\Delta x} = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} $
This means that the derivative is itself a function of $x$, telling us how $f(x)$ changes at any point.
There are several common ways to denote the derivative of $y = f(x)$. Some of the widely used notations in class 11 maths limits and derivatives include:
Here, the symbols $\frac{d}{dx}$ or $D$ represent the differential operator, which is used to calculate derivatives.
The operation on limits include sum, difference, constant multiplication, product, quotient, power and composition of functions.
Sum law for limits : $\lim\limits _{x \rightarrow a}(f(x)+g(x))=\lim\limits _{x \rightarrow a} f(x)+\lim\limits _{x \rightarrow a} g(x)=L+M$
Difference law for limits : $\lim\limits _{x \rightarrow a}(f(x)-g(x))=\lim\limits _{x \rightarrow a} f(x)-\lim\limits _{x \rightarrow a} g(x)=L-M$
Constant multiple law for limits : $\lim\limits _{x \rightarrow a} c f(x)=c \cdot \lim\limits _{x \rightarrow a} f(x)=c L$
Product law for limits : $\lim\limits _{x \rightarrow a}(f(x) \cdot g(x))=\lim\limits _{x \rightarrow a} f(x) \cdot \lim\limits _{x \rightarrow a} g(x)=L \cdot M$
Quotient law for limits : $\lim\limits _{x \rightarrow a} \frac{f(x)}{g(x)}=\frac{\lim\limits _{x \rightarrow a} f(x)}{\lim\limits _{x \rightarrow a} g(x)}=\frac{L}{M}$ for $M \neq 0$
Power law for limits : $\lim\limits _{x \rightarrow a}(f(x))^n=\left(\lim\limits _{x \rightarrow a} f(x)\right)^n=L^n$ for every positive integer $n$
Composition law of limit: $\lim\limits _{x \rightarrow a}(f \circ g)(x)=f\left(\lim\limits _{x \rightarrow a} g(x)\right)=f(M)$, only if $\mathrm{f}(\mathrm{x})$ is continuous at $\mathrm{g}(\mathrm{x})=\mathrm{M}$.
If $\lim\limits _{x \rightarrow a} f(x)=+\infty$ or $-\infty$, then $\lim\limits _{x \rightarrow a} \frac{1}{f(x)}=0$
Indeterminate forms arise in limits when the standard limit rules yield expressions that do not directly lead to a specific value. If we directly substitute $x = a$ in $f(x)$ while evaluating $\lim\limits _{x \rightarrow a} f(x)$ and will get one of the seven following forms $\frac{0}{0}, \frac{\infty}{\infty}, \infty-\infty, 1^{\infty}, 0^0, \infty^0, \infty \times 0$ then it is called indeterminate form.
Example: $\lim\limits _{x \rightarrow 2} \frac{x^2-4}{x-2}=\frac{0}{0}$ indeterminate form.
L'Hospital's Rule states that, if $\lim\limits _{x \rightarrow a} \frac{f(x)}{g(x)}$ is of $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form , then differentiate numerator and denominator till this intermediate form is removed. $\lim\limits _{x \rightarrow a} \frac{f(x)}{g(x)}=\lim\limits _{x \rightarrow a} \frac{f^{\prime}(x)}{g^{\prime}(x)}$
But, if we again get the indeterminate form $\frac{0}{0}$ or $\frac{\infty}{\infty} \lim\limits _{x \rightarrow a} \frac{f(x)}{g(x)}=\lim\limits _{x \rightarrow a} \frac{f^{\prime}(x)}{g^{\prime}(x)}=\lim\limits _{x \rightarrow a} \frac{f^{\prime \prime}(x)}{g^{\prime \prime}(x)}$ (so we differentiate numerator and denominator again)
This process is continued till the indeterminate form $\frac{0}{0}$ or $\frac{\infty}{\infty}$ is removed.
Example:
Evaluate $\lim\limits _{x \rightarrow 0} \frac{\sin x}{x}$
$
\lim\limits _{x \rightarrow 0} \frac{\sin x}{x}= \frac{0}{0}
$
But by L'Hospital rule, $\lim\limits _{x \rightarrow 0} \frac{\sin x}{x}=\lim\limits _{x \rightarrow 0} \frac{\cos x}{1}=1$
The differentiation of some basic functions are
1. $\frac{d}{d x}($ constant $)=0$
2. $\frac{d}{d x}\left(\mathbf{x}^{\mathbf{n}}\right)=\mathbf{n} \mathbf{x}^{\mathbf{n}-1}$
3. $\frac{d}{d x}\left(\mathbf{a}^{\mathrm{x}}\right)=\mathbf{a}^{\mathrm{x}} \log _{\mathrm{e}} \mathbf{a}$
4. $\quad \frac{d}{d x}\left(\mathrm{e}^{\mathrm{x}}\right)=\mathrm{e}^{\mathrm{x}} \log _{\mathrm{e}} \mathrm{e}=\mathrm{e}^{\mathrm{x}}$
5. $\frac{d}{d x}\left(\log _{\mathrm{e}}|\mathbf{x}|\right)=\frac{\mathbf{1}}{\mathbf{x}}, \quad \mathbf{x} \neq 0$
6. $\quad \frac{d}{d x}\left(\log _{\mathbf{a}}|\mathbf{x}|\right)=\frac{1}{\mathbf{x} \log _{\mathrm{e}} \mathbf{a}}, \quad \mathbf{x} \neq 0$
7. $\frac{d}{d x}(\sin (\mathbf{x}))=\cos (\mathbf{x})$
8. $\frac{d}{d x}(\cos (\mathbf{x}))=-\sin (\mathbf{x})$
9. $\frac{d}{d x}(\tan (\mathbf{x}))=\sec ^2(\mathbf{x})$
10. $\frac{d}{d x}(\cot (\mathbf{x}))=-\csc ^2(\mathbf{x})$
11. $\frac{d}{d x}(\sec (\mathbf{x}))=\sec (\mathbf{x}) \tan (\mathbf{x})$
12. $\frac{d}{d x}(\csc (\mathbf{x}))=-\csc (\mathbf{x}) \cot (\mathbf{x})$
The important rules of differentiation are
Let $f(x)$ and $g(x)$ be differentiable functions and $k$ be a constant. Then each of the following rules holds
The derivative of the sum of a function $f$ and a function $g$ is the same as the sum of the derivative of $f$ and the derivative of $g$.
$
\frac{d}{d x}(f(x)+g(x))=\frac{d}{d x}(f(x))+\frac{d}{d x}(g(x))
$
In general,
$
\frac{d}{d x}(f(x)+g(x)+h(x)+\ldots \ldots)=\frac{d}{d x}(f(x))+\frac{d}{d x}(g(x))+\frac{d}{d x}(h(x))+\ldots \ldots
$
The derivative of the difference of a function $f$ and $a$ function $g$ is the same as the difference of the derivative of $f$ and the derivative of $g$.
$
\begin{aligned}
& \frac{d}{d x}(f(x)-g(x))=\frac{d}{d x}(f(x))-\frac{d}{d x}(g(x)) \\
& \frac{d}{d x}(f(x)-g(x)-h(x)-\ldots \ldots)=\frac{d}{d x}(f(x))-\frac{d}{d x}(g(x))-\frac{d}{d x}(h(x))-\ldots \ldots
\end{aligned}
$
The derivative of a constant $k$ multiplied by a function $f$ is the same as the constant multiplied by the derivative of $f$
$
\frac{d}{d x}(k f(x))=k \frac{d}{d x}(f(x))
$
Let $f(x)$ and $g(x)$ be differentiable functions. Then,
$
\frac{d}{d x}(f(x) g(x))=g(x) \cdot \frac{d}{d x}(f(x))+f(x) \cdot \frac{d}{d x}(g(x))
$
This means that the derivative of a product of two functions is the derivative of the first function times the second function plus the derivative of the second function times the first function.
If three functions are involved, i.e let $k(x)=f(x) \cdot g(x) \cdot h(x)$
Let us have a function $\mathrm{k}(\mathrm{x})$ as the product of the function $\mathrm{f}(\mathrm{x}), \mathrm{g}(\mathrm{x})$ and $\mathrm{h}(\mathrm{x})$. That is, $k(x)=(f(x) \cdot g(x)) \cdot h(x)$. Thus,
$
k^{\prime}(x)=\frac{d}{d x}(f(x) g(x)) \cdot h(x)+\frac{d}{d x}(h(x)) \cdot(f(x) g(x))
$
[By applying the product rule to the product of $f(x) g(x)$ and $h(x)$.]
$
\begin{aligned}
& =\left(f^{\prime}(x) g(x)+g^{\prime}(x) f(x)\right) h(x)+h^{\prime}(x) f(x) g(x) \\
& =f^{\prime}(x) g(x) h(x)+f(x) g^{\prime}(x) h(x)+f(x) g(x) h^{\prime}(x)
\end{aligned}
$
Let $f(x)$ and $g(x)$ be differentiable functions. Then
$
\frac{d}{d x}\left(\frac{f(x)}{g(x)}\right)=\frac{g(x) \cdot \frac{d}{d x}(f(x))-f(x) \cdot \frac{d}{d x}(g(x))}{(g(x))^2}
$
OR
if $h(x)=\frac{f(x)}{g(x)}$, then $h^{\prime}(x)=\frac{f^{\prime}(x) g(x)-g^{\prime}(x) f(x)}{(g(x))^2}$
As we see in the following theorem, the derivative of the quotient is not the quotient of the derivatives.
If $u(x)$ and $v(x)$ are differentiable funcitons, then $u o v(x)$ or $u[v(x)]_{\text {is also differentiable. }}$
If $y=u o v(x)=u[v(x)]$, then
$
\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\mathrm{d} u\{v(x)\}}{\mathrm{d}\{v(x)\}} \times \frac{\mathrm{d}}{\mathrm{d} x} v(x)
$
is known as the chain rule. Or,
$
\text { If } y=f(u) \text { and } u=g(x) \text {, then } \frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\mathrm{d} y}{\mathrm{~d} u} \cdot \frac{\mathrm{d} u}{\mathrm{~d} x}
$
The chain rule can be extended as follows
If $y=[\operatorname{uovow}(x)]=u[v\{w(x)\}]$, then
$
\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\mathrm{d}[u[v\{w(x)\}]}{\mathrm{d} v\{w(x)\}} \times \frac{\mathrm{d}[v\{w(x)\}]}{\mathrm{d} w(x)} \times \frac{\mathrm{d}[w(x)]}{\mathrm{d} x}
$
This section covers all the important topics from limits and derivatives class 11 as per NCERT and JEE Main, helping students focus on key areas for better preparation.
Here you will find the best books and study materials that explain limits and derivatives clearly and provide practice questions aligned with the class 11 maths limits and derivatives syllabus.
Book Title | Author / Publisher | Description |
---|---|---|
NCERT Class 11 Mathematics | NCERT | Official textbook covering all fundamentals and exercises on limits and derivatives. |
Mathematics for Class 11 | R.D. Sharma | Detailed explanations, solved examples, and practice problems for limits and derivatives. |
Objective Mathematics | R.S. Aggarwal | Diverse MCQs and exercises for practice, including calculus basics. |
Arihant All-In-One Mathematics | Arihant | Comprehensive topic coverage with ample solved and unsolved problems. |
Calculus Made Easy | M.L. Khanna | Simplified approach to fundamental calculus concepts including limits and derivatives. |
This part lists the essential NCERT resources for studying limits and derivatives, which form the foundation for understanding concepts and solving problems effectively.
NCERT Maths Notes for Class 11th Chapter 13 - Limits and Derivatives
NCERT Maths Solutions for Class 11th Chapter 13 - Limits and Derivatives
NCERT Maths Exemplar Solutions for Class 11th Chapter 13 - Limits and Derivatives
In this section, you will get subject-specific NCERT resources that offer detailed explanations, examples, and solved questions related to class 11.
This section provides practice questions based on limits and derivatives, helping students strengthen their problem-solving skills and prepare for exams like JEE Main.
Frequently Asked Questions (FAQs)
Limits help us find the value a function approaches near a specific point, while derivatives measure how fast a function’s value is changing at that point.
For limits, common formulas include $ \lim_{x \to a} c = c $, $ \lim_{x \to a} x = a $, and trigonometric limits like $ \lim_{x \to 0} \frac{\sin x}{x} = 1 $. The derivative formula is $ f'(x) = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} $.
For a function to be differentiable at a point, it must be continuous there. Continuity ensures that limits exist and derivatives can be calculated.
If a limit tends to infinity, then the limit does not exist.
$\frac{0}{0}$ is not defined. It is called a indeterminate value. If a limit tends to indeterminate value