It's a Question of your Career!

Correct Answer: VSO

Solution : Given:
CAM : EES :: OAT : QEZ :: TOI : ?

Add the consecutive even numbers to the place value of the letters of CAM and OAT to get the related letter clusters.
CAM→C + 2 = E; A + 4 = E; M + 6 = S
So, CAM is related to EES.
OAT→O + 2 = Q; A + 4 = E; T + 6 = Z
So, OAT is related to QEZ.
Similarly, follow the same pattern for TOI –
T + 2 = V; O + 4 = S; I + 6 = O

So, TOI is related to VSO. Hence, the third option is correct.

Correct Answer: 90°

Solution :
In $\triangle$PQR, PQ = PR
⇒ $\angle$Q = $\angle$R = b
PM is the angle bisector of $\angle$P.
$\angle$QPM = $\angle$RPM = a
Apply angle sum property in $\triangle$PQR,
⇒ $\angle$P + $\angle$Q + $\angle$R = 180°
⇒ $\angle$P + b + b = 180°
⇒ $\angle$P = 180° – 2b
$\angle$QPM = $\frac{180° – 2b}{2}$ = 90° – b
In $\triangle$PQM,
Let $\angle$PMQ = $\theta$
⇒ $\angle$QPM + $\angle$Q + $\angle$M = 180°
⇒ 90° – b + b + $\theta$ = 180°
⇒ $\theta$ = 90°
Hence, the correct answer is 90°.

Correct Answer: 68%

Solution : The number of students who passed
= 80% of 20 + 60% of 30
= $\frac{80 × 20}{100}$ + $\frac{60 × 30}{100}$
= 16 + 18
= 34
Now, the pass percentage of the entire class
= $\frac{\text{Number of students passed}}{\text{Total students}}$ × 100
= $\frac{34}{(20 + 30)}$ × 100
= 68%
Hence, the correct answer is 68%.

Correct Answer: Bhagta Parab

Solution : The correct option is Bhagta Parab.

Bhagta Parab is an important festival celebrated by the tribal communities in Jharkhand, particularly by the Oraon tribe. This festival is associated with the worship of the deity Marang Buru, who is considered to be the protector of the community. Bhagta Parab is observed to seek blessings for the well-being of the community, the fertility of the land, and the prosperity of the people.

Correct Answer: i-b, ii-a, iii-d, iv-c

Solution : The correct answer is i-b, ii-a, iii-d, iv-c.

• Voltmeter: An instrument that measures voltage.
• Ammeter: an instrument that measures the magnitude of the current.
• Galvanometer: an instrument that measures the direction and magnitude of the current.
• Ohmmeter: An instrument that measures resistance.

Correct Answer: 3

Solution : Given: $\sqrt{11-3 \sqrt{8}}=a+b \sqrt{2}$
⇒ $\sqrt{11-3 \sqrt{2\times2\times2}}=a+b \sqrt{2}$
⇒ $\sqrt{9+2-2×3\sqrt{2}}=a+b \sqrt{2}$
⇒ $\sqrt{(3)^2+(\sqrt2)^2-2\times3\sqrt{2}}=a+b \sqrt{2}$
⇒ $\sqrt{(3-\sqrt{2})^2}=a+b \sqrt{2}$
⇒ $3-\sqrt{2}=a+b \sqrt{2}$
Comparing both sides, we get, $a=3,b=-1$
Now, $(2a+3b)$
= $(2\times3+3\times(-1))$
= $3$
Hence, the correct answer is 3.

Correct Answer: looking for his book

Solution : The correct choice is the third option.

In this context, looking for is the correct phrase to convey the idea of searching for his book. The preposition for is used with the verb looking to indicate the purpose or direction of the action whereas "looking into" means to investigate.

Therefore, the correct sentence is: He was looking for his book for the last two hours but couldn't find it.

Correct Answer: ENQWF

Solution : Given:
RAIN is written as TCKP.

Add 2 to the place value of each letter of RAIN to obtain the required code –
R + 2 = T; A + 2 = C; I + 2 = K; N + 2 = P
Thus, RAIN is coded as TCKP.
Similarly, follow the same pattern for CLOUD –
C + 2 = E; L + 2 = N; O + 2 = Q; U + 2 = W; D + 2 = F

So, CLOUD is coded as ENQWF. Hence, the first option is correct.

Correct Answer: 42 km/hr

Solution : Given: A person covers the first 25 km in 60 minutes and the next 38 km in 30 minutes.
Total distance = 25 + 38 = 63 km
Total time = (60 + 30) = 90 minutes = $\frac{90}{60}$ = $\frac{3}{2}$ hours
So, the average speed = $\frac{63}{\frac{3}{2}}$ = $63×\frac{2}{3}$ = 42 km/hr
Hence, the correct answer is 42 km/hr.

Correct Answer: $\frac{5}{9}$th of the marked price

Solution : Let the marked price = $p$ and the cost price = $q$
According to the question,
∴ 50% of $p$ = 90% of $q$
⇒ $\frac{p×50}{100}=\frac{q×90}{100}$
∴ $q=\frac{5}{9}p$
So, the cost price is $\frac{5}{9}$th of the marked price.
Hence, the correct answer is $\frac{5}{9}$th of the marked price.