An iron rod of 0.2 cm2 cross sectional area is subjected to a magnetizing field of 1200 A/m if the susceptibility of iron is 599
Answer (1)
Student Expert
25th Apr, 2019
Hello Megha,
Given: Magnetizing field = H = 1200 A/m, susceptibility = χ = 599, μo = 4π x 10-7 Wb/Am.
To Find: permeability = μ = ?, Magnetic flux per unit area = B = ?
Solution:
μ = μo ( 1 + χ)
∴ μ = 4π x 10-7 ( 1 + 599) = 4 x 3.142 x 10-7 x 600 = 7.536 x 10-4 H/m.
Now μ = B/H
∴ B = μ H = 7.536 x 10-4 x 1200 = 0.904 T
Ans: Permeability is 7.536 x 10-4 H/m and magnetic flux per unit area = 0.904 T
Thanku.
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