Question : Anuj and Anup have to travel from place A to place B in their respective cars. Anuj is driving at 70 km/hr and takes 3 halts of 10 minutes each, while Anup is driving at 80 km/hr and takes 4 halts of 15 minutes each. The time taken by Anup to reach place B, if Anuj takes 8.5 hours, is:
Option 1: 8 hours
Option 2: 7 hours
Option 3: 4 hours
Option 4: 6 hours
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Correct Answer: 8 hours
Solution :
Given: Time spent by Anuj on halts = (10 × 3 = 30) minutes = 0.5 hours
Anuj's speed = 70 km/hr.
He travels for 8.5 – 0.5 = 8 hours
$\text{Speed} = \frac{\text{Distance}}{\text{Time}}$
So, place B's distance from A = 70 × 8 = 560 km
Time spent by Anup on halts = (15 × 4 = 60) mins = 1 hour
Anup's speed = 80 km/hr
Time taken to travel 560 km = $\frac{560}{80}$ = 7 hours
$\therefore$ The total time Anup takes is 7 + 1 = 8 hours
Hence, the correct answer is 8 hours.
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