Question : In an isosceles triangle PQR, $\angle$P = 130°, If I is the in-centre of the triangle, what is the value of $\angle$QIR?
Option 1: 130°
Option 2: 120°
Option 3: 155°
Option 4: 165°
Answer (1)
24th Jan, 2024
Correct Answer: 155°
Solution :
Given:
$\angle$PQR = 130°, I is the incentre of the triangle.
So, $\angle$QIR = $90°+\frac{\angle PQR}{2}=90°+\frac{130°}{2}=155°$
Hence, the correct answer is 155°.
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