the emf of a primary cell is 2V . when it is short circuited , it gives a current of 4 A . Its internal resistance in ohm is
Answer (1)
14th Jan, 2020
EMF is the electromotive force of the cell. It is equal to the potential difference across the terminals of the cell when no current is flowing.
EMF = V+IR, where V is the voltage, I is the current flowing in the circuit and R is the internal resistance of the primary cell.
During short circuit, V=0.
So, EMF = 0+IR
Given:
EMF = 2V
I = 4A
So, resistance R = EMF/I
= 2/4
= 0.5 ohm
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