Pt Deen Dayal Mahavidyalaya, Ladampura All Questions

The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. As per the previous year cutoff trends with this rank the chances seems less to get a seat in NIT Tiruchirappalli & SPA Delhi.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. NITs cutoff varies to Home state quota & Other state quota, With this rank the chances seems less to get a seat in NITs & SPA Delhi, The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

Hello Gagandeep N A,

On the basis of the rank only the cutoff for college is decided.We can't predict the college.You can go for college predictor which Colleges are available for your percentile.

You can predict the college by your percentile from the link given below from careers 360 -

https://engineering.careers360.com/jee-main-architecture-college-predictor

You can use the above link by copying and pasting it in the url bar of your browser.

All the best!

Thanku.

Hello karan

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.For more colleges visit https://engineering.careers360.com/jee-main-college-predictor  .Hope this helps.

Good Luck!

Hey daran! Thanks for contacting careers 360.

For candidates to qualify for the admissions to nit's /iit's/ gfti etc they should have secured at least 75% marks in class 12 or be in the top 20 percentile in class 12 exam conducted by the respective boards.

You can refer to more information in this link provided by this website.

https://engineering.careers360.com/articles/new-eligibility-criteria-for-nits-and-iiits-admission-says-mhrd

Wish you all the best! 

Hey Sandeep.

You can use the formula given below to calculate JEE B.Arch Rank by percentile -   

(100- your total percentile score) * 1,45,386/ 100. 

According to your percentile, on applying this formula you can expect a rank around 10,600.

You can use the link which is given below to use the college predictor tool and see your probable chances. Https://engineering.careers360.com/jee-main-architecture-college-predictor   

Hello Kanchan. Thank you for choosing Careers360. 

According to the experts for JEE Mains paper 2,  the candidates who have 85 percentile or more have a high chance to qualify.

Also, to know your probable rank, you can use the formulae, (100-percentile) × 1,45,000 /100

Hope this helps!

Hello!Janitha

Your total Percentile is too low.But your percentile in mathematics is good.Rank will be given on the basis of total percentile score.Don't worry you still have one attempt for jee mains 2019.You have plenty of time in it.Focus on three sub(phy,chem and maths) equally.Try to balance among them.Solving 15 questions to each section in mains examination can enter you in good NITs.But, staying on one or two subject can depreciate your rank.So try to balance among three subject.

You can ask if you have any other queries.

GOOD LUCK!

The exact prediction would be difficult about the qualifying marks or rank as JEE Main is being conducted twice by NTA for the first time.

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 27,623.

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!