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Hello Gautom,

207 must be your marks in JEE mains paper 2.

In order to get your rank you have to tell your percentile. 

So please comment your percentile.


For more details you can get refrence from career 360 website :

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning


thanks


Hello,
Your rank would be around 46k by using the formula
145000*(100-percentile obtained)/100.
According to last year's cutoff you may not get a seat in any nit or central govt colleges.
Still you have a chance ,work hard for April paper
Good luck!

Dear aspirant, 

Your rank will be nearly (100-68.84)*145386/100=45302 based on previous year trends.And chances are less to be qualified to appear for jee advanced exam as experts predicted cutoff to be nearly 85 percentile for general candidate.

Good luck

Hi Vinslin,

This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 1163. Calculating marks using percentile is not possible and thus you will have to wait till it is released. To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: Https://engineering.careers360.com/articles/jee-main-paper-2-result

Thanks,

Hi Ishika Soni, 

Congratualtions on your succesfull results. This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 382. Calculating marks using percentile is not possible and thus you will have to wait till it is released. To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: 

https://engineering.careers360.com/articles/jee-main-paper-2-result

Thanks,

Hello Ishika,
Congratulations on scoring 99.73 in JEE mains mains paper 2 .
By using this formula :-

(100- your total percentile score) * 1,45,386/ 100.
(Note the rank calculated by this formula is approximate and should not be taken as actual rank, the actual rank by NTA may differ.)

Your rank is about 392 , which is a great rank by which You can easily get into many great Nit's, with the branch you want .
Look ahead to these colleges
1. Dr. B.R Ambedkar Nit.
2.Malviya Nit.
3.Maulana Azad Nit.
4.Motilal Nehru Nit.
I hope this helps.
Thank you.

Hello arjun,

Congratulations for your performance 

Total number of students appeared for jee main 2 paper id 180000.

So you can calculate your rank by this method:

180000×(100- obtained percentile)/100

By this your rank would be around 34000.

Good luck

Dear aspirant ,
Firstly congratulations for the result you have got. You can calculate your rank using Rank Formula = (100 - your total score) X 145386 /100.your rank is around 27623
Thank you


Hi,

Your percentile are very less for government college. You can go through the link provided below for more details .

All the best !!

https://engineering.careers360.com/jee-main-college-predictor

https://engineering.careers360.com/articles/jee-main-rank-list

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

Hello aspirant,

Thanks for contacting careers360.

As you belong to general category your Percentile is low.it is not possible to predict the college until nta declares the results for both the exams in April. Better concentrate on April exam and increase your Percentile. To know the college you get use this link.

https://engineering.careers360.com/jee-main-architecture-college-predictor

In case of any more queries feel free to contact. Thank you!
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