Hello,

Your expected will be around 182492.You can calculate your expected rank using the formula (100-your total percentile)*869010/100

where 869010 is the total number of candidates appeared in January session,In april session 1200000 candidates are expected to appear then your expected rank can be calculated using the formula (100-your total percentile)*1200000/100

Now, your category rank will be around 8k-9k.In 2019 a candidate belonging to SC category with rank 5763 secured a seat in ECE in NIT, Jalandhar.So you may have less chaces to get seat in this college.However, cut off is subjected to change it may increase or decrease slightly.

You  can predict the colleges in which you may get seat  by using the link below

https://engineering.careers360.com/jee-main-college-predictor

Hi dear,

Here is cutoff of NIT Jalandhar for pwd candidate for home state and other state respectively.

Cse-444.  243

Electrical engineering-2459 .   1070

ECE-868.    1061

IT-603

Above mentioned rank is pwd rank.

Hope it helps. For more queries please visit careers360.

Hello

Admission to NITs is done on the basis of rank secured by the candidate in JEE Main exam. The cutoff required for admission varies every year depending on various factors. Some of the factors that determine the cutoff are as follows:

• Total number of seats available
• Difficulty level of exam
• Previous year cutoff trends
• Number of candidates appearing for the exam
• Number of candidates applying for a course

It would be difficult to tell you exactly about the marks required for admission but I can provide you the JEE Main 2019 cutoff for reference and to have an idea about the rank required. JEE Main cutoff for admission to NIT Jalandhar for home state candidates stream wise is as follows-

Biotechnology- 109845
Chemical Engineering- 80428
Civil Engineering- 66379
Computer Science and Engineering- 9385
Electrical Engineering- 36722
Electrical and Communication Engineering- 20933

Do let us know if you have any other queries.

Good Luck!

Hi Shaurya,

Congratulations! Your first priority should be the course, as both colleges are almost equally reputed.

NIT Jalandhar fares better in the latest NIRF ranking list(42nd rank), though both colleges are among the top 100 in the country. The Mechanical department has a strict faculty, good placements (avg package 5-6 lakhs per year) and gives nice exposure to its students.

NIT Jamshedpur is also great in placements. EE is a good branch and has excellent opportunities in placements and research. Faculty is also decent. 

At the end of the day, it is your interest and abilities that matter for placements and higher studies. So you may choose according to your interest as you have to spend atleast next four years studying it. All the best.

Hii Aspirant

The fees is same for all Btech students branch does not matter,your total fees may approxiamately sum around 3lakhs for 4years of Btech.

Hope the details were helpful

For further more details about the college,please do refer the link given below:

https://www.careers360.com/university/dr-b-r-ambedkar-national-institute-of-technology-jalandhar

Thank You

Hi Abhishek,

No, Electrical Engineering at NIT Jalandhar has been there since the beginning, that is since 1987. You can confirm this by looking at placement statistics and an alumni base of NIT Jalandhar. Faculty of Electrical Engg. is very good, you can see their qualification in the link below:

http://www.nitj.ac.in/index.php/nitj_cinfo/FacultyList/6

All the best

Hello Abhishek,

According to their NIRF rankings, the universities in the same league as NIT, Jalandhar are - 

• National Institute of Technology Agartala
• National Institute of Technology Goa
• National Institute of Technology Jamshedpur
• National Institute of Technology Patna
• National Institute of Technology Raipur

Hope this helps.