In maths, there are various types of functions that we study. The process of determining whether a function is even or odd can be done by graphical method. They can be checked by plugging in the negative inputs (-x) in place of x into the function f(x) and considering the corresponding output values.These functions are crucial for numerous mathematical domains, such as algebra, calculus, and Fourier analysis.
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In this article, we will cover the concepts of the even and odd functions. This concept falls under the broader category of sets relation and function, a crucial chapter in class 11 Mathematics. It is not only essential for board exams but also for competitive exams like the Joint Entrance Examination (JEE Main), and other entrance exams such as SRMJEE, BITSAT, WBJEE, BCECE, and more. Over the last ten years of the JEE Main exam (from 2013 to 2023), a total of one question has been asked on this concept, including one in 2019.
Even and odd functions are functions which are classified based on the symmetry in functions.
For a real-valued function $f(x)$, when the output value of $f(-x)$ is the same as $f(x)$, for all values of $x$ in the domain of $f$, the function is said to be an even function which means that the negative sign does not affect the value of the function.
If for a function $f(x)$, $f(-x)=f(x)$ always hold true, then the function is known as an even function. Even functions are symmetric about the $y$-axis.
$y = x^2$
$ y = |x| $
$y = cos(x)$
Odd Function
When all values of $x$ in the domain of $f$ for a real-valued function $f(x)$ have an output value of $f(-x)$ equal to the negative of $f(x)$, the function is said to be odd. Which means that the negative sign does affect the value of the function.
If for a function $f(x) and f(-x)=-f(x)$ then the function is known as an odd function. Odd functions are symmetric about the origin.
$y = sin(x)$
$y = x^3$
Even Function: An even function satisfies equation $f(-x)=f(x)$, for all values of $x$ in $D(f)$, where $D(f)$ denotes the domain of the function $f$.
In other words, we can say that the equation $f(-x)-f(x)=0$ holds for an even function, for all $x$.
Odd Function:
The following equation is necessary to hold for an odd function. For all values of $x$ in $D(f)$, where $D(f)$ represents the function $f$'s domain, $f(-x)$ equals $-f(x)$.We can state that for each $x$, the equation $f(-x)+f(x)=0$ holds true for an odd function.
Even Function: $f(x)=x^2$. $f(-x)=(-x)^2=x^2$ for all values of $x$, as the square of a negative number is the same as the square of the positive value of the number. This implies $f(-x)=f(x)$, for all $x$. Hence, $f(x)=x^2$ is an even function.
Similarly, functions like $x^4, x^6, x^8$, etc. are even functions.
Odd Function: $f(x)=x^3$. $f(-x)=(-x)^3=-\left(x^3\right)$ for all values of $x$, as the cube of a negative number is the same as the negative of the cube of the positive value of the number. This means that $f(-x)=-$ $f(x)$, for all $x$. Hence, $f(x)=x^3$ is an odd function.
Similarly, functions like $x^5, x^7$, $x^9$, etc. are odd functions.
How to Check Even and Odd Functions?
To know how to check even and odd functions, the following methods can be used.
Algebraic Method:
Graphical Method:
NOTE: We can have functions that are neither even nor odd. Eg, $ y = x+1$
Even Function: The graph of an even function remains unchanged when reflected across the $y$-axis. For example, $y=x^2$
Odd Function: The graph of an odd function remains unchanged when rotated $180$ degrees around the origin. For example, $y=x^3$
Even function | Odd function |
$f(-x) = f(x)$ | $f(-x) = -f(x)$ |
The graph of an even function is symmetric with respect to the y-axis. | The graph of an odd function is symmetric with respect to the origin. |
Here, the y-axis acts like a mirror. That means if we flip vertically, the graph looks the same. | Here, if we spin the graph upside down about the origin, it looks the same. |
Examples: $x^2, x^4,$\cos x, \ldots$ | Examples: $x,x^3, x^5, \ldots$ |
Both types of functions exhibit some properties as discussed below:
Addition and Subtraction:
Multiplication:
Multiplication:
Even in the field of trigonometry, we have the concept of even and odd functions as very useful. The various quadrants in the 2-D plane carry different signs of trigonometric ratios. Their nature changes with sign as the quadrant changes.In the first quadrant , all six trigonometric ratios have positive values. In the second quadrant, only sine and cosecant are positive. In the third quadrant, only tangent and cotangent are positive. In the fourth quadrant, only cosine and secant are positive.
Now to check whether a function is even or odd, we take the help of a unit circle. A unit circle can be used to check if a trigonometric ratio is even or odd in nature. An angle measured in anticlockwise direction is a positive angle whereas the angle measured in the clockwise direction is a negative angle.
We know that the integral of a function always gives the area below the curve.If the function is even or odd, and provided that the interval is [-a, a], we can apply the following two rules:
Fourier series is the representation of periodic function as the sum of sine and cosines. The fourier series of a periodic function with period $2L$ is $f(x)=a_0+\sum_{n=1}^{\infty}\left[a_n \cos \left(\frac{n \pi x}{L}\right)+b_n \sin \left(\frac{n \pi x}{L}\right)\right]$ where $a_0=\frac{1}{2 L} \int_{-L}^L f(x) d x$, $a_n=\frac{1}{L} \int_{-L}^L f(x) \cos \left(\frac{n \pi x}{L}\right) d x$ and .$b_n=\frac{1}{L} \int_{-L}^L f(x) \sin \left(\frac{n \pi x}{L}\right) d x$.
Fourier series of even function: The sine terms $\left(b_n\right)$ disappears because $\sin (-x)=-\sin (x)$. Integrating an odd function over a symmetric interval results in zero. Only the sine terms will remain in the fourier series.
Fourier series of odd function: The cosine terms $\left(a_n\right)$ vanish because $\cos (-x)=\cos (x)$. Integrating an odd function multiplied by an even function over a symmetric interval results in zero. Only the cosine terms will remain in the fourier series.
Now let us look into the fourier series formula for even and odd functions.
Even function: Fourier series formula for even functions is $f(x)=a_0+\sum_{n=1}^{\infty} a_n \cos \left(\frac{n \pi x}{L}\right)$ where $a_n=\frac{2}{L} \int_0^L f(x) \cos \left(\frac{n \pi x}{L}\right) d x$.
Odd function: Fourier series formula for odd functions is $f(x)=\sum_{n=1}^{\infty} b_n \sin \left(\frac{n \pi x}{L}\right)$ where $b_n=\frac{2}{L} \int_0^L f(x) \sin \left(\frac{n \pi x}{L}\right) d x$.
Example 1: The graph of the function $y=f(x)$ is symmetrical about the line $x=2$, then
1) $f(x)=f(-x)$
2) $f(2+x)=f(2-x)$
3) $f(x+2)=f(x-2)$
4) $f(x)=-f(-x)$
Solution:
Since a graph is symmetric about the $y$-axis means $x=0$ then it is even function and $f(-x)=f(x)$
$\therefore \quad \mathrm{f}(0-\mathrm{x})=\mathrm{f}(0+\mathrm{x}) \quad(\mathrm{b}<\mathrm{z}$ it is symmetric about $\mathrm{v}=0)$
But in question, it is symmetric about $x=2$ then $f(2-x)=f(2+x)$
Hence, the answer is option 2 .
Example 2: Which of the following functions is an even function?
1) $x^6+3 x^3-5$
2) $x^6+3 x^4-5$
3) $x^6+3 x^3-5 x$
4) $x^6+3 x^4-5 x$
Solution:
|f $f(x)=x^6+3 x^4-5$
$f(-x)=x^6+3 x^4-5=f(x)$
Hence, it is an even function
Hence, the answer is option 2.
Example 3: Which of the following functions is an even function?
1) $\sin x$
2) $\cos x$
3) $\tan x$
4) $\csc x$
Solution:
Even Function -
$f(-x)=f(x)$
Symmetric about $\gamma_{\text {-axis }}$
If $f(x)=\cos x$
then $f(-x)=\cos (-x)=\cos x$
Hence, the answer is option 2 .
Example 4: A function $f$ from the set of natural numbers to integers defined by
$f(n)=\left\{\begin{array}{l}\frac{n-1}{2}, \text { when } n \text { is odd } \\ -\frac{n}{2}, \text { when } n \text { is even is }\end{array}\right.$
1) onto but not one-one
2) one-one and onto both
3) neither one-one nor onto
4) one-one but not onto.
Solution:
$f(x)= \begin{cases}\frac{n-1}{2} & \text { when } n \text { is odd } \\ -\frac{n}{2} & \text { when } n \text { is even }\end{cases}$
$f(1) = 0$
$f(2) = -1$
$f(3) = 1$
$f(4) = 2$
$f(5) = 2$
Clearly, this pattern will cover all the integers, hence onto
Also, it is a one-one function
Hence, the answer is option 2
Example 5: The function $f(x)=\log \left(x+\sqrt{x^2+1}\right)$
1) an odd function
2) a periodic function
3) neither an even nor an odd function
4) an even function.
Solution:
As we learned in
Odd Function -
$f(-x)=-f(x)$
- wherein
Symmetric about origin
$\begin{aligned}
& f(x)=\log \left(x+\sqrt{1+x^2}\right) \\
& f(-x)=\log \left(-x+\sqrt{1+x^2}\right) \\
& f(x)+f(-x)=\log \left(\sqrt{1+x^2}+x\right)+\log \left(\sqrt{1+x^2}-x\right) \\
& =\log \left(1+x^2-x^2\right)=\log 1=0
\end{aligned}$
It is an odd function.
Hence, the answer is the option 1.
It is defined as a relation between a set of inputs having one output each.
It is an even function.
The graph of an even function remains unchanged when reflected across the y-axis.
If for a function f(x),f(−x)=−f(x) then the function is known as an odd function.
The graph of an odd function remains unchanged when rotated 180 degrees around the origin.
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