Transcendental function is a category of functions that cannot be expressed as finite polynomials, algebraic functions, or solutions of algebraic equations with rational coefficients. They are crucial in advanced mathematics and have applications across various scientific fields. These are non-algebraic functions.
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In this article, we will cover the concepts of the transcendental function especially exponential and logarithmic functions. This concept falls under the broader category of sets relation and function, a crucial Chapter in class 11 Mathematics. It is not only essential for board exams but also for competitive exams like the Joint Entrance Examination (JEE Main), and other entrance exams such as SRMJEE, BITSAT, WBJEE, BCECE, and more. Over the last ten years of the JEE Main exam (from 2013 to 2023), a total of seven questions have been asked on this concept, including two in 2019, and five in 2023.
The transcendental function can be defined as a function that is not algebraic and cannot be expressed in terms of a finite sequence of algebraic operations such as $\sin x$.
The most familiar transcendental functions examples are the exponential functions, logarithmic functions, trigonometric functions, hyperbolic functions, and inverse of all these functions. The less familiar transcendental functions examples are Gamma, Elliptic, and Zeta functions.
A polynomial equation is an equation in the form of
1. $x^4-4 x^2-3=0$
2. $4 x^2-3 x+9=0$
3. $2 x^3-5 x^2-7 x+3=0$
are some of the algebraic equations.
An equation containing polynomials, logarithmic functions, trigonometric functions, and exponential functions is known as transcendental equation.
1. $\tan x-e^x=0$
2. $\sin x-x e^{2 x}=0$
3. $x e^x=\cos x$
are some of the transcendental equations examples.
A transcendental equation is an equation into which transcendental functions (such as exponential, logarithmic, trigonometric, or inverse trigonometric) of one of the variables (s) have been solved for. Transcendental equations do not have closed-form solutions.
Transcendental equations examples includes:
1. $x=e^{-x}$
2. $x=\cos x$
Exponential Function: function $f(x)$ such that $f(x)=a^x$ is known as an exponential function.
base: $a>0, a \neq 1$
domain : $x \in \mathbb{R}$
range : $\mathrm{f}(\mathrm{x})>0$
Property : If $a^x=a^y$,then $x=y$
Properties
Logarithmic function: function $f(x)$ such that $f(x)=\log _a(x)$ is called logarithmic function
base: $a>0, a \neq 1$
domain : $\mathrm{x}>0$
range $: f(x) \in \mathbb{R}$
1. $\log _e(a b)=\log _e a+\log _e b$
2. $\log _e\left(\frac{a}{b}\right)=\log _e a-\log _e b$
3. $\log _e a^{\mathrm{m}}=m \log _e a$
4. $\log _a a=1$
5. $\log _{\mathrm{b}^{\mathrm{m}}} \mathrm{a}=\frac{1}{\mathrm{~m}} \log _{\mathrm{b}} \mathrm{a}$
6. $\log _b a=\frac{1}{\log _{\mathrm{a}} \mathrm{b}}$
7. $\log _b a=\frac{\log _m a}{\log _m b}$
8. $\mathrm{a}^{\log _a m}=\mathrm{m}$
9. $\mathrm{a}^{\log _c \mathrm{~b}}=\mathrm{b}^{\log _c \mathrm{a}}$
10. $\log _{\mathrm{m}} \mathrm{a}=\mathrm{b} \Rightarrow \mathrm{a}=\mathrm{m}^{\mathrm{b}}$
Trigonometry functions or circular functions are sine, cosine and tangent they are used in the analysis of periodic behavior. These functions also show time periodicity and are used nearly in all branches of science and application like physics, engineering, and signal processing.
Properties
Examples
Such functions, like hyperbolic sine sinh(x) and hyperbolic cosine cosh(x), are analogues of trigonometric functions but for a hyperbola.
Properties
Examples
The Transcendental functions show the following properties:
The applications of the Transcendental functions are as follows:
Example 1: What is the range of the function $f(x)=\left|a^x\right|$ ?
1) $[1, \infty)$
2) $R$
3) $R^{+}$
4) $[0, \infty)$
Solution:
$\begin{aligned}
& a^x>0 \forall x \equiv R \\
& \text { Thus }\left|a^x\right|=a^x \\
& \text { Hence }\left|a^x\right|>0 \quad \forall x \equiv R \\
& \text { i.e }\left|a^x\right| \in R^{+}
\end{aligned}$
Hence, the answer is the option 3.
Example 2: The number of real roots of the equation $5+\left|2^x-1\right|=2^x\left(2^x-2\right)$ is:
Solution:
$\begin{aligned}
& 5+\left|2^x-1\right|=2^x\left(2^x-2\right) \\
& 5+\left|2^x-1\right|=2^{2 x}-2 \cdot 2^x
\end{aligned}$
$\begin{aligned}
& \text { Case 1: } x \geq 0 \\
& =>5+2^x-1=2^{2 x}-2 \cdot 2^x \\
& =>2^{2 x}-2 \cdot 2^x-2^x-4=0 \\
& =>\left(2^x-4\right)\left(2^x+1\right)=0 \\
& =>2^x-4=0 \\
& \Rightarrow x=2
\end{aligned}$
Case 2: $x<0$
$\begin{aligned}
& 5+1-2^x=2^{2 x}-2 \cdot 2^x \\
& =>6=2^{2 x}-2^x \\
& \text { LHS }=+ \text { ve } \& \text { RHS }=- \text { ve (no solution) } \\
& \therefore \text { no. of solution }=1
\end{aligned}$
Hence, the answer is 1.
Example 3: Which of the following is the domain of $f(x)=\log _2(x+4)$
1) $(0, \infty)$
2) $(-2, \infty)$
3) $(-4, \infty)$
4) None of these
Solution:$\begin{aligned}
& \ln \log _2(x+4) ; x+4>0 \\
& \text { i.e } x>-4
\end{aligned}$
Hence, the answer is the option 3.
Example 4: If $f(x)=\log _c\left(\frac{1-x}{1+x}\right),|x|<1, \underset{\text { then }}{ } f\left(\frac{2 x}{1+x^2}\right)$ is equal to
1) $2 f\left(x^2\right)$
2) $2 f(x)$
3) $-2 f(x)$
4) $(f(x))^2$
Solution:
$\begin{aligned}
& f(x)=\log _e\left(\frac{1-x}{1+x}\right),|x|<1 \\
& f\left(\frac{2 x}{1+x^2}\right)=? \\
& f\left(\frac{2 x}{1+x^2}\right)=\log _e\left(\frac{1-\frac{2 x}{1+x^2}}{1+\frac{2 x}{1+x^2}}\right) \\
& =\log _e\left(\frac{\frac{1+x^2-2 x}{1+x^2}}{\frac{1+x^2+2 x}{1+x^2}}\right) \\
& =\log _e \frac{x^2-2 x+1}{x^2+2 x+1}=\log _e\left(\frac{(1-x)^2}{(x+1)^2}\right) \\
& =\log _e\left(\frac{1-x}{x+1}\right)^2
\end{aligned}$
$\begin{aligned}
& =2 \log _e\left(\frac{1-x}{x+1}\right),|x|<1 \\
& =2 f(x)
\end{aligned}$
Hence, the answer is the option 2.
Example 5: The number of solutions of the equation $\log _4(x-1)=\log _2(x-3)$ is
Solution:
$\begin{aligned}
& \log _4(x-1)=\log _2(x-3) \\
& \Rightarrow \frac{1}{2} \log _2(x-1)=\log _2(x-3) \\
& \Rightarrow \log _2(x-1)^{1 / 2}=\log _2(x-3) \\
& \Rightarrow \sqrt{x-1}=(x-3) \\
& \Rightarrow x-1=x^2+9-6 x \\
& \Rightarrow x^2-7 x+10=0 \\
& \Rightarrow(x-2)(x-5)=0 \\
& \Rightarrow x=2,5
\end{aligned}$
but $x$ can't be 2 , because in
$\log _2(x-3) \rightarrow x>3$
So, there is only one solution
Hence, the answer is 1 .
Transcendental function is a category of functions that cannot be expressed as finite polynomials, or algebraic functions.
Examples of transcendental functions include the exponential function, the logarithm, and the trigonometric functions.
A transcendental function is defined as a function that cannot be obtained by a finite number of operations as a solution of an algebraic equation. These functions often arise as solutions of differential equations and are typically obtained through Taylor series expansions.
An equation which contains polynomials, trigonometric functions, logarithmic functions, exponential functions etc., is called a Transcendental equation. For example, $\tan x – e^x = 0$; $\sin x – xe^{2x} = 0; x e^x = \cos x$ are transcendental equations.
Transcendental numbers are irrational, but not all irrational numbers are transcendental. For example, $x^2 – 2 = 0$ has the solutions $x = ± √2$; thus, Square root of $√2$, an irrational number, is an algebraic number and not transcendental.
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