Trigonometric Integrals

Trigonometric Integrals

Edited By Komal Miglani | Updated on Jul 02, 2025 08:02 PM IST

Trigonometric integral is one of the important parts of Calculus, which applies to measuring the change in the function at a certain point. Mathematically, it forms a powerful tool by which slopes of functions are determined, the maximum and minimum of functions found, and problems on motion, growth, and decay, to name a few. These integration concepts have been broadly applied in branches of mathematics, physics, engineering, economics, and biology.

Trigonometric Integrals
Trigonometric Integrals

In this article, we will cover the concept of Trigonometric integral. This concept falls under the broader category of Calculus, a crucial Chapter in class 12 Mathematics. It is not only essential for board exams but also for competitive exams like the Joint Entrance Examination (JEE Main), and other entrance exams such as SRMJEE, BITSAT, WBJEE, BCECE, and more. Over the last ten years of the JEE Main exam (from 2013 to 2023), three questions have been asked on this concept, including one in 2013, one in 2021, and one in 2023.

Trigonometric Integrals

Integration is the reverse process of differentiation. In integration, we find the function whose differential coefficient is given. The rate of change of a quantity y concerning another quantity x is called the derivative or differential coefficient of y concerning x. Geometrically, the Differentiation of a function at a point represents the slope of the tangent to the graph of the function at that point. These functions are also known as arcus functions, cyclometric functions, or anti-trigonometric functions. These functions are used to get an angle for a given trigonometric value. It refers to the change in the value of the trigonometric function at a certain rate.

(a) Integral of the form

1. $\int \frac{1}{a \cos ^2 x+b \sin ^2 x} d x$
2. $\int \frac{1}{a+b \sin ^2 x} d x$
3. $\int \frac{1}{a+b \cos ^2 x} d x$
4. $\int \frac{1}{a+b \sin ^2 x+c \cos ^2 x} d x$

Working Rule:

Step 1: Divide the numerator and denominator both by $\cos ^2 x$.
Step 2 : Put $\tan x=t, \sec ^2 x \mathrm{dx}=\mathrm{dt}$

This substitution will convert the trigonometric integral into an algebraic integral.

After employing these steps the integral will reduce to the form $\int \frac{f(t) d t}{A t^2+B t+C}$, where $f(t)$ is a polynomial in $t$.
This integral can be evaluated by methods we studied in previous concepts.

(b) Integral of the form

1. $\int \frac{1}{a \sin x+b \cos x} d x$
2. $\int \frac{1}{a+b \sin x} d x$
3. $\int \frac{1}{a+b \cos x} d x$
4. $\int \frac{1}{a \sin x+b \cos x+c} d x$

Working Rule:

Write sin x and cos x in terms of tan (x/2) and then substitute for tan (x/2) = t

i.e.

$\sin x=\frac{2 \tan x / 2}{1+\tan ^2 x / 2}$ and $\cos x=\frac{1-\tan ^2 x / 2}{1+\tan ^2 x / 2}$
replace, $\tan (\mathrm{x} / 2)$ with $t$
by performing these steps the integral reduces to the form
$\int \frac{1}{a t^2+b t+c} \mathrm{dt}$ which can be solved by method we studied in previous concepts.

(c) Integrals of the form

1. $\int \frac{p \cos x+q \sin x+r}{a \cos x+b \sin x+c} d x$
2. $\int \frac{p \cos x+q \sin x}{a \cos x+b \sin x} d x$

Working Rule:

Express numerator as $\lambda($ denominator $)+\mu($ differentiation of denominator $)+\gamma$

$\Rightarrow(\mathrm{p} \cos \mathrm{x}+\mathrm{q} \sin \mathrm{x}+\mathrm{r})=\lambda(\mathrm{a} \cos \mathrm{x}+\mathrm{b} \sin \mathrm{x}+\mathrm{c})+\mu(-\mathrm{a} \sin \mathrm{x}+\mathrm{b} \cos x)+\gamma$

where $\lambda, \mu$, and \gamma are constants to be determined by comparing the coefficients of $\sin x, \cos \mathrm{x}$, and constant terms on both sides.

$\begin{aligned}
\int \frac{p \cos \mathrm{x}+\mathrm{q} \sin \mathrm{x}+\mathrm{r}}{a \cos \mathrm{x}+\mathrm{b} \sin \mathrm{x}+\mathrm{c}} \mathrm{dx}= & \int \frac{\lambda(\mathrm{a} \cos \mathrm{x}+\mathrm{b} \sin \mathrm{x}+\mathrm{c})+\mu(-\mathrm{a} \sin \mathrm{x}+\mathrm{b} \cos \mathrm{x})+\gamma}{\mathrm{a} \cos \mathrm{x}+\mathrm{b} \sin \mathrm{x}+\mathrm{c}} \mathrm{dx} \\
= & \lambda \int \frac{a \cos x+b \sin x+c}{a \cos x+b \sin x+c} d x+\mu \int \frac{-a \sin x+b \cos x}{a \cos x+b \sin x+c} d x \\
& \quad+\int \frac{\mu}{\mathrm{a} \cos \mathrm{x}+\mathrm{b} \sin \mathrm{x}+\mathrm{c}} \mathrm{dx} \\
= & \lambda x+\mu \ln |a \cos x+b \sin x+c|+\int \frac{\mu}{a \cos x+b \sin x+c} d x
\end{aligned}$

Recommended Video Based on Trigonometric Integrals


Solved Questions Based on Trigonometric Integrals

Example 1: Integrate $\int \frac{d x}{\sin ^2 x+2 \sin x \cos x}$

1) $\ln \frac{t+1}{t-1}+c$
2) $\ln \frac{t+2}{t}+c$
3) $\frac{1}{2} \ln \frac{t}{(t+2)}+C$
4) none of these

Solution
Divide by $\cos ^2 x$ in each case and pull $t=\tan x, d t=\sec ^2 x d x$

$\int \frac{d x \sec ^2 x}{\tan ^2 x+2 \tan x}=\int \frac{d t}{(t+1)^2-1}=\frac{1}{2} \ln \frac{t}{(t+2)}+C$


Hence, the answer is the option 3.
Example 2: $\int \frac{d x}{1+\sin x}$
1) $\frac{1}{1+\tan \left(\frac{x}{2}\right)}+C$

2) $-\frac{2}{\tan \left(\frac{x}{2}\right)+1}+C$
3) $\frac{1}{1+\cot \left(\frac{x}{2}\right)}+C$
4) $-\frac{1}{1+\cot \left(\frac{x}{2}\right)}+C$

$\begin{aligned}
& I=\int \frac{1}{\sin (x)+1} \mathrm{~d} x \\
& =\int \frac{\sec ^2\left(\frac{x}{2}\right)}{\left(\tan \left(\frac{x}{2}\right)+1\right)^2} \mathrm{~d} x \\
& \text { Put } u=\tan \left(\frac{x}{2}\right)+1 \Rightarrow \mathrm{d} x=\frac{2}{\sec ^2\left(\frac{x}{2}\right)} \mathrm{d} u \\
& I=2 \int \frac{1}{u^2} d u \\
& =-\frac{2}{u} \\
& =-\frac{2}{\tan \left(\frac{x}{2}\right)+1}+C
\end{aligned}$

Hence, the answer is the option (2).

Example 3: $\int \frac{d x}{3+4 \cos ^2 x}$ equals
1) $\frac{\sqrt{3}}{\sqrt{7}} \tan ^{-1}\left(\sqrt{\frac{3}{7}} \tan x\right)+C$
2) $\frac{1}{\sqrt{21}} \tan ^{-1}\left(\sqrt{\frac{3}{7}} \tan x\right)+C$

$\sqrt{3} \tan ^{-1}\left(\sqrt{\frac{3}{7}} \tan x\right)+C$

4) None of these

Solution
Divide numerator and denominator by $\cos ^2 x$

$\begin{aligned}
& \int \frac{\sec ^2 x d x}{3 \sec ^2 x+4} \\
& =\int \frac{\sec ^2 x d x}{3 \tan ^2 x+3+4} \\
& =\int \frac{\sec ^2 x d x}{7+3 \tan ^2 x}
\end{aligned}$

Put $\tan x=t \Rightarrow \sec ^2 x d x=d t$

$\begin{aligned}
& \int \frac{d t}{7+3 t^2} \\
& =\frac{1}{3} \int \frac{d t}{t^2+\left(\sqrt{\frac{7}{3}}\right)^2} \\
& =\frac{1}{3} \times \frac{\sqrt{3}}{\sqrt{7}} \tan ^{-1}\left(\sqrt{\frac{3}{7}} \tan x\right)+C \\
& =\frac{1}{\sqrt{21}} \tan ^{-1}\left(\sqrt{\frac{3}{7}} \tan x\right)+C
\end{aligned}$

Hence, the answer is the option 2.

Example 4: Integrate $\int \frac{d x}{\sin ^2 x+2 \cos ^2 x+2 \sin x \cos x}$
1) $x+c$
2) $\frac{1}{2} \tan ^{-1}(1+x)+C$
3) $\tan ^{-1}(1+\tan x)+C$

4) None of these

Solution

Divide by $\cos^{2} x$

$\begin{aligned}
& \int \frac{\sec ^2 x \cdot d x}{\tan ^2 x+2+2 \tan x} \\
& I=\int \frac{\sec ^2 x d x}{(\tan x+1)^2+1}
\end{aligned}$

Put $\tan (x)=t$

$\sec ^2 x d x=d t$

$\begin{aligned}
& I=\int \frac{d t}{(t+1)^2+1} \\
& =\tan ^{-1}(t+1)+C \\
& =\tan ^{-1}(\tan x+1)+C
\end{aligned}$

Hence, the answer is the option 3.

Example 5: $\int \frac{d x}{1+2 \cos x}$
1) $\frac{1}{\sqrt{3}} \ln \left|\frac{\sqrt{3}+\tan \frac{x}{2}}{\sqrt{3}-\tan \frac{x}{2}}\right|+c$
2) $-\frac{1}{\sqrt{3}} \cdot \ln \left|\frac{\tan \left(\frac{x}{2}\right)-\sqrt{3}}{\tan \left(\frac{x}{2}\right)+\sqrt{3}}\right|+c$
3) $\frac{2}{\sqrt{3}} \ln \left|\frac{\sqrt{3}+\tan \frac{x}{2}}{\sqrt{3}-\tan \frac{x}{2}}\right|+c$
4) None of these

Solution

$\begin{aligned} & \int \frac{d x}{1+2 \cos x} \\ & \int \frac{d x}{1+\frac{2-2 \tan ^2 \frac{x}{2}}{1+\tan ^2 \frac{2}{2}}} \\ & =\int \frac{\sec ^2\left(\frac{x}{2}\right) \cdot d x}{3-\tan ^2\left(\frac{x}{2}\right)} \\ & \text { Put } u=\tan \left(\frac{x}{2}\right) \Rightarrow \frac{1}{2} \sec ^2\left(\frac{x}{2}\right) \cdot d x=d u \\ & =-2 \int \frac{1}{u^2-3} d u \\ & =-\frac{1}{\sqrt{3}} \cdot \ln \left|\frac{u-\sqrt{3}}{u+\sqrt{3}}\right|+c \\ & =-\frac{1}{\sqrt{3}} \cdot \ln \left|\frac{\tan \left(\frac{x}{2}\right)-\sqrt{3}}{\tan \left(\frac{x}{2}\right)+\sqrt{3}}\right|+c\end{aligned}$Hence, the answer is the option (2).

Summary

Trigonometric integral is an important concept used in practical and traditional approaches in mathematics. Trigonometric integrals are integrals that involve trigonometric functions such as sine, cosine, tangent, and their inverses.

Frequently Asked Questions (FAQs)

1. What is integration?

Integration is the reverse process of differentiation.

2. What is the other name of integration?

The other name of integration is antiderivative.

3. What is the integration of sin x?

An integration of sin x is -cos x.

4. What is an integration of cos x?

An integration of cos x is sin x.

5. What is an integration of sec x tanx?

An integration of sec x tan x is sec x.

6. How do you integrate sin²x?
To integrate sin²x, we use the half-angle formula: sin²x = (1 - cos2x)/2. The integral becomes:
7. How do you handle integrals involving secant and tangent functions?
Integrals involving secant and tangent often use the identity sec²x = 1 + tan²x. A common technique is to make a substitution u = tanx, which transforms du = sec²x dx. This substitution can simplify many secant and tangent integrals.
8. What is the significance of the integral ∫sec x dx?
The integral ∫sec x dx is significant because it doesn't have an obvious antiderivative. Its solution, ln|sec x + tan x| + C, is often memorized but can be derived using substitution and partial fractions. This integral serves as a building block for more complex trigonometric integrals.
9. What is the significance of the integral ∫sec x dx?
The integral ∫sec x dx is significant because its antiderivative, ln|sec x + tan x| + C, is not immediately obvious. This integral serves as a building block for more complex trigonometric integrals and appears frequently in physics and engineering applications. Understanding how to derive and use this result is crucial for advanced integration techniques.
10. How do you integrate tan²x?
To integrate tan²x, we use the identity tan²x = sec²x - 1. The integral becomes:
11. How do you approach integrals of the form ∫sin(ax) cos(bx) dx?
For integrals of the form ∫sin(ax) cos(bx) dx, we use the product-to-sum formula: sin(ax) cos(bx) = (1/2)[sin(a+b)x + sin(a-b)x]. This transforms the integral into a sum of simpler trigonometric functions that are easier to integrate.
12. What are trigonometric integrals and why are they important?
Trigonometric integrals are integrals that involve trigonometric functions like sine, cosine, and tangent. They are important because they appear frequently in physics, engineering, and other applied sciences when dealing with periodic phenomena or circular motion. Understanding these integrals helps in solving real-world problems involving waves, oscillations, and rotational mechanics.
13. How do you recognize a trigonometric integral?
Trigonometric integrals typically contain trigonometric functions (sin, cos, tan, sec, csc, cot) either in the integrand or in the limits of integration. They may also include combinations or products of these functions. Recognizing these patterns is crucial for choosing the appropriate integration technique.
14. What is the fundamental trigonometric identity and how does it help in integration?
The fundamental trigonometric identity is sin²θ + cos²θ = 1. This identity, along with its variations, is crucial in simplifying trigonometric expressions during integration. It allows us to substitute one trigonometric function for another, often making the integral easier to solve.
15. What is the "odd power" rule for integrating sineⁿx or cosineⁿx?
The "odd power" rule states that for odd powers of sine or cosine, we can use a substitution to reduce the power. For example, for ∫sin³x dx, we rewrite it as ∫sin²x · sinx dx, substitute sin²x = 1 - cos²x, and then integrate. This rule helps simplify integrals with odd powers of trigonometric functions.
16. What is the strategy for integrating products of sines and cosines?
For products of sines and cosines, we often use the product-to-sum formulas to convert the product into a sum of simpler trigonometric functions. For example, sin x cos x = (1/2)sin(2x). This strategy simplifies the integral and makes it easier to solve.
17. What is the technique for integrating ∫tan x dx?
To integrate ∫tan x dx, we use the identity tan x = sin x / cos x and then make a substitution. The steps are:
18. How do you handle integrals involving inverse trigonometric functions?
Integrals involving inverse trigonometric functions often require substitution or integration by parts. For example, to integrate ∫arcsin x dx, we use integration by parts with u = arcsin x and dv = dx. This leads to x arcsin x + √(1-x²) + C. Understanding these techniques is crucial for solving more complex trigonometric integrals.
19. What is the strategy for integrating ∫sin³x dx?
For ∫sin³x dx, we use the "odd power" rule. We rewrite it as ∫sin²x · sin x dx, then substitute sin²x = 1 - cos²x:
20. How do you approach integrals of the form ∫sinⁿx cosᵐx dx?
For integrals of the form ∫sinⁿx cosᵐx dx, the strategy depends on whether n and m are odd or even. If one is odd, we can use substitution. If both are even, we often use half-angle formulas or reduction formulas. For example, if n is odd, we might substitute u = cos x to reduce the integral to a polynomial in u.
21. What is the importance of reduction formulas in trigonometric integration?
Reduction formulas are crucial for integrating higher powers of trigonometric functions. They allow us to express an integral with higher powers in terms of integrals with lower powers. For example, ∫sinⁿx dx can be expressed in terms of ∫sinⁿ⁻²x dx. These formulas provide a systematic way to tackle complex trigonometric integrals.
22. How do you integrate ∫sec³x dx?
To integrate ∫sec³x dx, we use the identity sec²x = 1 + tan²x:
23. What is the method for integrating ∫csc x cot x dx?
For ∫csc x cot x dx, we recognize this as the derivative of csc x. Therefore:
24. How do you handle integrals involving products of secant and tangent?
Integrals involving products of secant and tangent often use the substitution u = sec x. For example, for ∫sec x tan x dx:
25. What is the strategy for integrating ∫sin(ln x) dx?
For ∫sin(ln x) dx, we use substitution:
26. How do you approach integrals of the form ∫e^(ax) sin(bx) dx?
For integrals of the form ∫e^(ax) sin(bx) dx, we use integration by parts twice. Let u = e^(ax) and dv = sin(bx) dx for the first application, then reverse the roles for the second. This leads to a linear equation in the original integral, which can be solved algebraically. This technique is crucial for integrals combining exponential and trigonometric functions.
27. What is the significance of the integral ∫dx/(a² + x²)?
The integral ∫dx/(a² + x²) is significant because it results in (1/a)arctan(x/a) + C. This is a fundamental form that appears in many applications and is related to the inverse tangent function. Understanding this integral helps in solving more complex rational functions involving trigonometric substitutions.
28. How do you integrate ∫sec x tan x dx?
To integrate ∫sec x tan x dx, we recognize it as the derivative of sec x:
29. What is the method for integrating ∫sin²x cos²x dx?
For ∫sin²x cos²x dx, we can use the double angle formula: sin²x cos²x = (1/4)sin²(2x)
30. How do you handle integrals involving tan⁻¹(x)?
Integrals involving tan⁻¹(x) often require integration by parts. For example, ∫tan⁻¹(x) dx:
31. What is the strategy for integrating ∫cos⁴x dx?
For ∫cos⁴x dx, we use the power reduction formula: cos²x = (1 + cos(2x))/2
32. How do you approach integrals of the form ∫sin(ax²) dx?
Integrals of the form ∫sin(ax²) dx don't have elementary antiderivatives. They are related to Fresnel integrals, which are important in optics and signal processing. While we can't find a closed-form solution, we can approximate these integrals numerically or express them in terms of special functions. This highlights the limitations of elementary integration techniques and the need for advanced methods in some cases.
33. What is the technique for integrating ∫csc²x dx?
To integrate ∫csc²x dx, we recognize it as the negative derivative of cot x:
34. How do you handle integrals involving products of sine and exponential functions?
For integrals involving products of sine and exponential functions, like ∫e^x sin x dx, we use integration by parts twice:
35. What is the significance of the integral ∫dx/√(1-x²)?
The integral ∫dx/√(1-x²) is significant because it results in arcsin(x) + C. This is a fundamental form that appears in many applications and is related to the inverse sine function. It's also the basis for trigonometric substitution in more complex integrals. Understanding this integral is crucial for solving problems involving circular motion and periodic phenomena.
36. How do you integrate ∫tan³x dx?
To integrate ∫tan³x dx, we use the identity tan²x = sec²x - 1:
37. What is the method for integrating ∫sec x tan²x dx?
For ∫sec x tan²x dx, we use the identity tan²x = sec²x - 1:
38. How do you approach integrals of the form ∫sin(ax) sin(bx) dx?
For integrals of the form ∫sin(ax) sin(bx) dx, we use the product-to-sum formula:
39. How do you integrate ∫cos(x²) dx?
The integral ∫cos(x²) dx doesn't have an elementary antiderivative. It's relate

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Arrange the following Cobalt complexes in the order of incresing Crystal Field Stabilization Energy (CFSE) value. Complexes :  

\mathrm{\underset{\textbf{A}}{\left [ CoF_{6} \right ]^{3-}},\underset{\textbf{B}}{\left [ Co\left ( H_{2}O \right )_{6} \right ]^{2+}},\underset{\textbf{C}}{\left [ Co\left ( NH_{3} \right )_{6} \right ]^{3+}}\: and\: \ \underset{\textbf{D}}{\left [ Co\left ( en \right )_{3} \right ]^{3+}}}

Choose the correct option :
Option: 1 \mathrm{B< C< D< A}
Option: 2 \mathrm{B< A< C< D}
Option: 3 \mathrm{A< B< C< D}
Option: 4 \mathrm{C< D< B< A}

The type of hybridisation and magnetic property of the complex \left[\mathrm{MnCl}_{6}\right]^{3-}, respectively, are :
Option: 1 \mathrm{sp ^{3} d ^{2} \text { and diamagnetic }}
Option: 2 \mathrm{sp ^{3} d ^{2} \text { and diamagnetic }}
Option: 3 \mathrm{sp ^{3} d ^{2} \text { and diamagnetic }}
Option: 4 \mathrm{sp ^{3} d ^{2} \text { and diamagnetic }}
Option: 5 \mathrm{d ^{2} sp ^{3} \text { and diamagnetic }}
Option: 6 \mathrm{d ^{2} sp ^{3} \text { and diamagnetic }}
Option: 7 \mathrm{d ^{2} sp ^{3} \text { and diamagnetic }}
Option: 8 \mathrm{d ^{2} sp ^{3} \text { and diamagnetic }}
Option: 9 \mathrm{d ^{2} sp ^{3} \text { and paramagnetic }}
Option: 10 \mathrm{d ^{2} sp ^{3} \text { and paramagnetic }}
Option: 11 \mathrm{d ^{2} sp ^{3} \text { and paramagnetic }}
Option: 12 \mathrm{d ^{2} sp ^{3} \text { and paramagnetic }}
Option: 13 \mathrm{sp ^{3} d ^{2} \text { and paramagnetic }}
Option: 14 \mathrm{sp ^{3} d ^{2} \text { and paramagnetic }}
Option: 15 \mathrm{sp ^{3} d ^{2} \text { and paramagnetic }}
Option: 16 \mathrm{sp ^{3} d ^{2} \text { and paramagnetic }}
The number of geometrical isomers found in the metal complexes \mathrm{\left[ PtCl _{2}\left( NH _{3}\right)_{2}\right],\left[ Ni ( CO )_{4}\right], \left[ Ru \left( H _{2} O \right)_{3} Cl _{3}\right] \text { and }\left[ CoCl _{2}\left( NH _{3}\right)_{4}\right]^{+}} respectively, are :
Option: 1 1,1,1,1
Option: 2 1,1,1,1
Option: 3 1,1,1,1
Option: 4 1,1,1,1
Option: 5 2,1,2,2
Option: 6 2,1,2,2
Option: 7 2,1,2,2
Option: 8 2,1,2,2
Option: 9 2,0,2,2
Option: 10 2,0,2,2
Option: 11 2,0,2,2
Option: 12 2,0,2,2
Option: 13 2,1,2,1
Option: 14 2,1,2,1
Option: 15 2,1,2,1
Option: 16 2,1,2,1
Spin only magnetic moment of an octahedral complex of \mathrm{Fe}^{2+} in the presence of a strong field ligand in BM is :
Option: 1 4.89
Option: 2 4.89
Option: 3 4.89
Option: 4 4.89
Option: 5 2.82
Option: 6 2.82
Option: 7 2.82
Option: 8 2.82
Option: 9 0
Option: 10 0
Option: 11 0
Option: 12 0
Option: 13 3.46
Option: 14 3.46
Option: 15 3.46
Option: 16 3.46

3 moles of metal complex with formula \mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{3} gives 3 moles of silver chloride on treatment with excess of silver nitrate. The secondary valency of CO in the complex is_______.
(Round off to the nearest integer)
 

The overall stability constant of the complex ion \mathrm{\left [ Cu\left ( NH_{3} \right )_{4} \right ]^{2+}} is 2.1\times 10^{1 3}. The overall dissociation constant is y\times 10^{-14}. Then y is ___________(Nearest integer)
 

Identify the correct order of solubility in aqueous medium:

Option: 1

Na2S > ZnS > CuS


Option: 2

CuS > ZnS > Na2S


Option: 3

ZnS > Na2S > CuS


Option: 4

Na2S > CuS > ZnS


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