Did you know that deuterons are found in a type of hydrogen which is called heavy hydrogen, and have some amazing real-life uses? They help us create clean energy by powering fusion reactors and are also used in cancer treatment in which they help to destroy harmful cell without affecting the healthy ones and many more. In this article, we are going to study about deuterons definition history and more. Keep continuing with the article to know in depth about deuterons
JEE Main 2025: Physics Formula | Study Materials | High Scoring Topics | Preparation Guide
JEE Main 2025: Syllabus | Sample Papers | Mock Tests | PYQs | Study Plan 100 Days
NEET 2025: Syllabus | High Scoring Topics | PYQs
A deuteron is a very small (tiny) part of an atom, which is a type of hydrogen atom called heavy hydrogen or deuterium. Deutron has one neutron and one proton inside it.
Deuteron symbol is represented as 12D. A non-aligned atom of 2H is termed as deuterium. It is the unpretentious bound state of nucleons and thus gives us an ideal system for learning the nucleon-nucleon interaction. For nuclear physicists, the deuterons should be what the hydrogen atoms are for atomic physicists.
$
\begin{array}{|l|l|}
\hline \text { Form of Mass } & \text { Value } \\
\hline \text { Mass in Atomic Mass Units (amu) } & 2.013553212745(40) \mathrm{u} \\
\hline \text { Mass in MeV/c² } & 1875.612928(12) \mathrm{MeV} / \mathrm{c}^2 \\
\hline \text { Mass in Kilograms (kg) } & 3.3435837724 \times 10^{-27} \mathrm{~kg} \\
\hline \text { Mass in Grams (g) } & 3.3435837724 \times 10^{-24} \mathrm{~g} \\
\hline \text { Mass in Joules (J) (via } E=m c^2 \text { ) } & 3.005 \times 10^{-10} \mathrm{~J} \\
\hline \text { Mass in Electron Volts (eV) } & 1.875612928 \times 10^9 \mathrm{eV} \\
\hline \text { Mass in Energy Equivalent (GeV) } & 1.875612928 \mathrm{GeV} \\
\hline
\end{array}
$
Deuteron | Deuterium |
The nucleus of deuterium, consisting of one proton and one neutron. | An isotope of hydrogen with one proton, one neutron, and one electron. |
²H⁺ or d (for deuteron nucleus, positively charged). | ²H or D (for deuterium atom, neutral charge). |
Positively charged (as it lacks the electron). | Electrically neutral (proton and electron balance). |
1 proton and 1 neutron (no electron). | 1 proton, 1 neutron, and 1 electron. |
Deuteron gets its name from the Greek word “deuteros”, which means “second”. It refers to the two particles that make up the nucleus. Harold Urey first discovered it in 1931. Deuteron’s stability has been noteworthy since its discovery.
After knowing about properties of deuteron, now move to the mass and charge of deuteron.
Let us explain deuteron Mass and Charge. Deuterium is an atomic particle with a proton and neutron that is stable. Hydrogen-2 is indicated by the letters D or 2H. The mass of a deuteron is measured in atomic mass units (2.0135 amu) or million electron volts (1875.612928 MeV). The deuteron has a charge of +1e. This is because protons are present.
In Mass Doublet Method, two nearby masses are used i. e. Having the same value of mass number. In the mass spectrograph both ions are produced simultaneously in the ions source and are focused as two nearly lines.
The formation of hydrocarbon with great variety of mass numbers provides a convenient method of mass comparison with a doublet method.
Following determinations have been made:
$
\begin{gathered}
m\left(\mathrm{C}_6 \mathrm{H}_{12}\right)-m\left(\mathrm{C}_6 \mathrm{D}_6\right)=(9.289710 \pm 0.000024) \times 10^{-3} \mathrm{u} \\
6 m(\mathrm{C})+12 m(\mathrm{H})-6 m(\mathrm{C})-6 m(\mathrm{D})=9.289710 \times 10^{-3} \mathrm{u} \\
12 m(\mathrm{H})-6 m(\mathrm{D})=9.289710 \times 10^{-3} \mathrm{u}
\end{gathered}
$
Using $m\left({ }^1 \mathrm{H}\right)=1.007825037 \mathrm{u}$,
$
\begin{gathered}
12 \times 1.007825037-6 m(\mathrm{D})=9.289710 \times 10^{-3} \mathrm{u} \\
m\left({ }^2 \mathrm{H}\right)=2.014101789 \pm 0.000000021 \mathrm{u}
\end{gathered}
$
$\begin{aligned} & \qquad 5 m(\mathrm{C})+12 m(\mathrm{D})-6 m(\mathrm{C})-6 m(\mathrm{D})=9.289710 \times 10^{-3} \mathrm{u} \\ & \text { Using } m\left({ }^{12} \mathrm{C}\right)=12 \mathrm{u}, \\ & m\left({ }^2 \mathrm{H}\right)=2.014101771 \pm 0.000000015 \mathrm{u}\end{aligned}$
These accurate values are in very good arrangement.
With this mass of 2H and using the measured ¹H and neutron masses, we can find the binding energy
$B=\left[m\left({ }^1 \mathrm{H}\right)+m(n)-m\left({ }^2 \mathrm{H}\right)\right] c^2=2.22463 \pm 0.00004 \mathrm{MeV}$
We can also determine this binding energy directly by bringing a proton and a neutron (n) together to form 2H and measuring the energy of the γ- ray photon that is emitted:
${ }^1 \mathrm{H}+\mathrm{n} \rightarrow{ }^2 \mathrm{H}+\mathrm{Y}$
The resultant binding energy, which is equal to the observed energy of the photon less a small recoil correction, is 2.224589 ± 0.000002 MeV, in excellent agreement with the mass spectroscopic value. A third method, called photo dissociation, uses the reverse reaction,
$\gamma+{ }^2 \mathrm{H} \rightarrow{ }^1 \mathrm{H}+n$
In which a - ray photon breaks apart a deuteron. The minimum - ray energy that accomplishes this process is equal to the binding energy (again, corrected for the recoil of the final products). The observed value is 2.224 ± 0.002 MeV, in good agreement with the mass spectroscopic value.
Also check-
A deuteron (2H nucleus) comprises of a neutron and a proton. (A non-aligned atom of 2H is termed as deuterium.). It is the unpretentious bound state of nucleons and thus gives us an ideal system for learning the nucleon-nucleon interaction. Deuteron symbol is represented as 12D.
Mass of deuteron in kg is 3.343 x 10-27 kg.
Deuteron’s binding energy is given by 2.22463 MeV
Harold Urey first discovered it in 1931.
The quadruple moment of deuteron is determined by radio frequency molecular beam method.
12 Nov'24 09:44 PM
10 Oct'24 02:57 PM
08 Oct'24 03:32 PM
24 Sep'24 05:17 PM
11 Sep'24 10:01 PM
29 Aug'24 09:52 AM