It's a Question of your Career!

Thank you for providing your details. Let's assess your chances of securing admission to SASTRA University.

Your Profile:

• JEE Mains Percentile : 76.7

• TS Board Marks : 910 out of 1000

• Category : Not specified (assuming General)

SASTRA University Admission Process:

SASTRA University offers two streams for B.Tech admissions:

• Stream 1 (50% of seats) :

Weightage : 75% Class 12 marks + 25% JEE Mains score

Eligibility : Candidates should have a minimum of 90% in Class 12 and 100+ marks in JEE Mains .

• Stream 2 (50% of seats) :

Eligibility : Admission based solely on Class 12 marks. Candidates should have a minimum of 95% in Class 12 .

Your Score Calculation:

Using the formula for Stream 1 :

• Class 12 Marks : 910/1000 = 91%

• JEE Mains Percentile : 76.7

For Stream 1 :

• Class 12 Weightage : 91% × 0.75 = 68.25

• JEE Mains Weightage : 76.7 × 0.25 = 19.175

Total Score = 68.25 + 19.175 = 87.425 out of 100

This score is below the typical cutoff for top branches like Computer Science Engineering (CSE) and Electronics and Communication Engineering (ECE), which generally require a combined score above 90.

Admission Possibilities:

• Stream 1 : With a score of 87.425, securing admission to CSE or ECE is unlikely . However, you may have a chance in lower-demand branches such as Mechanical, Civil, or Electrical Engineering, depending on seat availability and category reservations.

• Stream 2 : Since your Class 12 marks are 91%, which is below the 95% threshold, Stream 2 is not applicable .

Recommendations:

• Apply for lower-demand branches : Consider applying for branches like Mechanical or Civil Engineering, where the competition may be less intense.

• Explore other institutions : If you're specifically interested in CSE or ECE, you might want to consider other universities or colleges where your profile aligns better with their admission criteria.

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Based on your JEE Main percentile and TS board marks, let's assess your chances of getting a seat at SASTRA University. SASTRA primarily considers two streams for B.Tech admissions:

• Stream 1: 70% of the seats are filled based on a combination of JEE Main score (25% weightage) and normalized Class XII marks (75% weightage).
• Stream 2: The remaining 30% of the seats are filled solely based on normalized Class XII marks (100% weightage).

With a 76.7 percentile in JEE Main, your performance in this entrance exam is a significant factor for Stream 1. To estimate your potential in Stream 1, we would need to know your approximate JEE Main score corresponding to this percentile. However, a 76.7 percentile generally suggests a decent score that will contribute to your combined score.

Your Telangana board marks of 910 are also crucial, especially for Stream 2. SASTRA normalizes the Class XII marks from different boards to create a merit list for this stream. A high score like 910 indicates a strong academic performance in your board exams, which will be highly beneficial for admission through Stream 2.

Given that SASTRA considers both JEE Main scores and board marks, you have a good chance of securing a seat. Your high board marks will be advantageous for both streams. For Stream 1, your JEE Main percentile will be combined with your normalized board marks. For Stream 2, you will be considered solely based on your normalized board marks.

I hope this helps.

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With 970 marks in IPE and an 81% in JEE Mains, your eligibility for a Computer Science Engineering (CSE) seat at SASTRA University depends on the admission stream.

Stream 1 (70% seats): This stream considers 75% weightage for 12th marks and 25% for JEE Mains. For a competitive rank, a combined score (12th marks × 0.75 + JEE score × 0.25) should be high. While specific cutoffs vary annually, previous data suggests that candidates with higher JEE percentiles and 12th marks above 90% have better chances .

Stream 2 (30% seats): This stream admits students based solely on 12th marks. With 970 marks, you may have a chance, but competition is intense, and higher marks are typically preferred .

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Hi Adhya! Congratulations on clearing JEE Advanced !

Based on your JEE Advanced scores:

• CRL Rank : 304880

• OBC-NCL Rank : 107412

Admission Possibilities in NITs and IIITs :

With your OBC-NCL rank of 107412 , here’s what you can expect:

• Top NITs (like NIT Trichy, Warangal, Surathkal, etc.) and IIITs (like IIIT Hyderabad) will likely be out of reach for branches like CSE , as they typically require a much lower rank.

• However, for lower-ranked NITs and IIITs , you may have a chance for branches like:

Information Technology (IT)

Software Engineering

Electronics and Communication Engineering (ECE)

Some NITs that might still offer you a seat in IT or related branches are:

• NIT Durgapur

• NIT Goa

• NIT Sikkim

• NIT Mizoram

• NIT Nagaland

• NIT Puducherry

IIITs :

For IIITs , the competition is high for CSE , but you may still have a chance in newer IIITs like:

• IIIT Kota

• IIIT Bhagalpur

• IIIT Nagpur

• IIIT Kalyani

Other Good Options:

If you are interested in CSE or related branches , here are a few private universities that offer strong computer science programs:

• VIT Vellore

• SRM Institute of Science and Technology

• Shiv Nadar University

• Amrita University

• Manipal University

These institutions offer CSE , Software Engineering , and related branches and have a high reputation, with good campus placements.

Summary:

• Top NITs and IIITs : Unlikely for CSE with your rank, but branches like IT, Software Engineering, and ECE may be possible in lower-ranked institutions.

• Private Universities : You have a strong chance in institutions like VIT , SRM , Shiv Nadar , and Amrita .

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