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22 Views

Question : Directions: A father is 5 times as old as his son. His son is 6 years old. After how many years, will the father be 4 times as old as his son?

Option 1: 5 years

Option 2: 6 years

Option 3: 4 years

Option 4: 2 years

Team Careers360 26th Jan, 2024

Correct Answer: 2 years


Solution : Given:
The present age of the son = 6 years
The father's present age is five times the age of his son,
⇒ Father's present age = 6 × 5 = 30 years

Let's assume that after Y years, his father's age will be four times his son's age.
After Y years, Father's age = (30 + Y) years, his son's age = (6 + Y) years

According to the given statement,
⇒ 4 × (6 + Y) = (30 + Y)
⇒ 24 + 4Y = 30 + Y
⇒ 4Y – Y = 30 – 24
⇒ 3Y = 6
⇒ Y = 2

So, after 2 years the age of the father will be 4 times as old as his son. Hence, the fourth option is correct.

8 Views

Question : Directions: After interchanging the given two numbers (not digits) what will be the values of expression (I) and (II) respectively?
6 and 4
l. 10 × 6 – 30 ÷ 4 + 20
II. 8 – 4 × 5 + 6 ÷ 2

Option 1: 12 and –6

Option 2: 20 and 55

Option 3: 55 and –20

Option 4: 10 and –6

Team Careers360 26th Jan, 2024

Correct Answer: 55 and –20


Solution : Given:
l. 10 × 6 – 30 ÷ 4 + 20
II. 8 – 4 × 5 + 6 ÷ 2

Let's solve each equation after interchanging the numbers according to the instructions.
On interchanging the numbers 6 and 4 in the first equation, we get –
= 10 × 4 – 30 ÷ 6 + 20
= 10 × 4 – 5 + 20
= 40 – 5 + 20
= 55
On interchanging the numbers 6 and 4 in the second equation, we get –
= 8 – 6 × 5 + 4 ÷ 2
= 8 – 6 × 5 + 2
= 8 – 30 + 2
= –20

Therefore, after solving the given equations the required answer is 55 and –20. Hence, the third option is correct.

6 Views

Question : $x$ does $\frac{1}{4}$ of a job in 6 days. $y$ completes the rest of the job in 12 days. Then $x$ and $y$ could complete the job together in:

Option 1: $9$ days

Option 2: $9\frac{3}{5}$ days

Option 3: $8\frac{1}{8}$ days

Option 4: $7\frac{1}{3}$ days

Team Careers360 26th Jan, 2024

Correct Answer: $9\frac{3}{5}$ days


Solution : Time taken by $x$ to complete $\frac{1}{4}$ of a job = 6 days
Time taken by $x$ to complete whole work = 6 × 4 = 24 days
Part of work done by $x$ in a day = $\frac{1}{24}$
Time taken by $y$ to complete $\frac{3}{4}$ of a job = 12 days
Time taken by $y$ to complete whole work = $\frac{12 × 4}{3}$ = 16 days
Part of work done by $y$ in a day = $\frac{1}{16}$
Part of work done by $x$ and $y$ in a day = $\frac{1}{24}$ + $\frac{1}{16}$ = $\frac{4 + 6}{96}$ = $\frac{10}{96}$
Time taken by $x$ and $y$ together to complete whole work = $\frac{96}{10}$ = $9\frac{3}{5}$ days
Hence, the correct answer is $9\frac{3}{5}$ days.

17 Views

Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at (1), (2), and (3) that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).

The work you have submitted is not to the mark.

(1) as the 

(2) from the

(3) up to the mark

(4) No Improvement

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 26th Jan, 2024

Correct Answer: (3)


Solution : The sentence can be improved using the third option.

This is the correct phrase in English to convey that something meets the expected standard or is satisfactory. "The work you have submitted is not up to the mark", indicates that the work does not meet the required or expected standard.

Therefore, the correct sentence is: The work you have submitted is not up to the mark.

10 Views

Question : Select the most appropriate ANTONYM of the word "established" from the given sentence:
Siben feels great satisfaction and gratified when he finds his pupils established successfully in the society when a lot have been displaced because of several failed attempts.

Option 1: displaced

Option 2: fail

Option 3: gratified

Option 4: pupils

Team Careers360 26th Jan, 2024

Correct Answer: displaced


Solution : The right option is the first option.

Established implies being settled, well-founded, or having achieved success, while displaced means being removed, unsettled, or forced to leave a place, which is its antonym in this context.

So, the meanings of the other given words are:

  • Fail means to be unsuccessful or to not achieve the desired objective.
  • Gratified means to be pleased or satisfied as a result of achieving or fulfilling something.
  • Pupil refers to a student or a learner, especially in a school or educational setting.

So, the most appropriate antonym of established is displaced.

15 Views

Question : Directions: Select the option related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
CAM : EES :: OAT : QEZ :: TOI : ?

Option 1: USO

Option 2: VTO

Option 3: VSO

Option 4: VSP

Team Careers360 27th Jan, 2024

Correct Answer: VSO


Solution : Given:
CAM : EES :: OAT : QEZ :: TOI : ?

Add the consecutive even numbers to the place value of the letters of CAM and OAT to get the related letter clusters.
CAM→C + 2 = E; A + 4 = E; M + 6 = S
So, CAM is related to EES.
OAT→O + 2 = Q; A + 4 = E; T + 6 = Z
So, OAT is related to QEZ.
Similarly, follow the same pattern for TOI –
T + 2 = V; O + 4 = S; I + 6 = O

So, TOI is related to VSO. Hence, the third option is correct.

4 Views

Question : In $\triangle$PQR, the angle bisector of $\angle$P intersects QR at M. If PQ = PR, then what is the value of $\angle$PMQ?

Option 1: 75°

Option 2: 80°

Option 3: 70°

Option 4: 90°

Team Careers360 26th Jan, 2024

Correct Answer: 90°


Solution :
In $\triangle$PQR, PQ = PR
⇒ $\angle$Q = $\angle$R = b
PM is the angle bisector of $\angle$P.
$\angle$QPM = $\angle$RPM = a
Apply angle sum property in $\triangle$PQR,
⇒ $\angle$P + $\angle$Q + $\angle$R = 180°
⇒ $\angle$P + b + b = 180°
⇒ $\angle$P = 180° – 2b
$\angle$QPM = $\frac{180° – 2b}{2}$ = 90° – b
In $\triangle$PQM,
Let $\angle$PMQ = $\theta$
⇒ $\angle$QPM + $\angle$Q + $\angle$M = 180°
⇒ 90° – b + b + $\theta$ = 180°
⇒ $\theta$ = 90°
Hence, the correct answer is 90°.

21 Views

Question : A class is divided into two sections, with 20 students in one section and 30 students in the other. The pass percentages for these sections are 80% and 60%, respectively. What is the pass percentage for the entire class?

Option 1: 60%

Option 2: 68%

Option 3: 70%

Option 4: 78%

Team Careers360 27th Jan, 2024

Correct Answer: 68%


Solution : The number of students who passed
= 80% of 20 + 60% of 30
= $\frac{80 × 20}{100}$ + $\frac{60 × 30}{100}$
= 16 + 18
= 34
Now, the pass percentage of the entire class
= $\frac{\text{Number of students passed}}{\text{Total students}}$ × 100
= $\frac{34}{(20 + 30)}$ × 100
= 68%
Hence, the correct answer is 68%.

19 Views

Question : Which of the following festivals is observed by the tribal people of Jharkhand?

Option 1: Nongkrem

Option 2: Losar

Option 3: Suata

Option 4: Bhagta Parab

Team Careers360 26th Jan, 2024

Correct Answer: Bhagta Parab


Solution : The correct option is Bhagta Parab.

Bhagta Parab is an important festival celebrated by the tribal communities in Jharkhand, particularly by the Oraon tribe. This festival is associated with the worship of the deity Marang Buru, who is considered to be the protector of the community. Bhagta Parab is observed to seek blessings for the well-being of the community, the fertility of the land, and the prosperity of the people.

16 Views

Question : Match the columns.

Instrument Their Function
i. Voltmeter a. An instrument that measures the magnitude of the current
ii. Ammeter b. An instrument that measures voltage
iii.Galvanometer c. An instrument that measures resistance
iv. Ohmmeter d. An instrument that measures the direction and the magnitude of the current

Option 1: i-a, ii-c, iii-b, iv-d

Option 2: i-b, ii-a, iii-d, iv-c

Option 3: i-b, ii-a, iii-c, iv-d

Option 4: i-a, ii-b, iii-c, iv-d

Team Careers360 26th Jan, 2024

Correct Answer: i-b, ii-a, iii-d, iv-c


Solution : The correct answer is i-b, ii-a, iii-d, iv-c.

  • Voltmeter: An instrument that measures voltage.
  • Ammeter: an instrument that measures the magnitude of the current.
  • Galvanometer: an instrument that measures the direction and magnitude of the current.
  • Ohmmeter: An instrument that measures resistance.
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