0.16g of methane is subjected to combustion at 27c in a bomb calorimeter system
Answer (1)
1st Jun, 2020
Hello!!!
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Heat of combustion at constant volume (ΔE)
Δ E= heat capacity * Δ T* moles
Δ E = 17.7*0.5*16/0.16
by solving the abouve equation,we get Δ E= -885 kJ/mole
Heat of combustion at constant pressure Δ H=Δ E+Δ ngRT
Reaction for Combustion of Methane is CH4+2O2 gives rise to CO2+2H2O(l)
Δng= -2,R=8.314*10^-3Kj/mol k,T=300K
Δ H= -885-2*8.314*10^-3*300
By solving thus we get Δ H= -890KJ
Hope it helps!!!!
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