1 N 40%(w/w)of NaoH in water so find molarity and molality?
Answer (1)
N=M*n
1=M*1
M=1
m = w *1000/m*w.
(%w/w=40 so 40gm of Naoh in 100gm of solution so w of H2O=100-40=60)
m=40*1000/40*60
m=16.67
1=M*1
M=1
m = w *1000/m*w.
(%w/w=40 so 40gm of Naoh in 100gm of solution so w of H2O=100-40=60)
m=40*1000/40*60
m=16.67
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