1.TALLAHASSEE permutation? How many of these arrangements have no adjacent A? 2.Select 5 cards from a standard deck of 52 cards how many ways can the selection result in a hand with a)No clubs b)which have at least 1 club.
Answer (1)
13th Dec, 2020
Hi Candidate,
The TALLAHASSEE permutation is a special case of Permutation and Combination in the- Tallahassee has 11 letters therefore there are 11! ... One permutation of the letters would be TALLAHA"S1""S2"EE but this cannot be differentiated in practice from.
In the second question, it's asked for the total number of ways to choose 5 cards from the pack of 52, in which there are no Clubs. So, we have to choose 5 cards from 39 (52-13), which is equal to 39P5, where P refers to Permutation.
Hope that this answer helps you.
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