Question : 20 litres of a mixture contains 20% alcohol and the rest is water. If 4 litres of water is mixed in it, the percentage of alcohol in the new mixture will be:
Option 1: $33\frac{1}{3}\%$
Option 2: $16\frac{2}{3}\%$
Option 3: $25\%$
Option 4: $12\frac{1}{2}\%$
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Correct Answer: $16\frac{2}{3}\%$
Solution :
Given:
In 20 litres of a mixture, 20% is alcohol and the rest is water.
4 litres of water is added to it.
In 20 litres of mixture,
Alcohol = 20 × ($\frac{20}{100}$) = 4 litres
Water = 20 – 4 = 16 litres
On adding 4 litres of water,
Quantity of water = 16 + 4 = 20 litres
Quantity of mixture = 20 + 4 = 24 litres
$\therefore$ The required percentage of alcohol $= \frac{4}{24}× 100 = \frac{50}{3}\% = 16\frac{2}{3}\%$
Hence, the correct answer is $16\frac{2}{3}\%$.
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