300j of work is done in sliding a 2kg block up an inclined plane of height 10m. Workdone against friction is
Answer (1)
17th Dec, 2018
Hi
Greetings
Thework done on the object =change in potential energy + friction loss
WeWork done on the object equal to 300 joules.
Increase in potential energy equal to MgH=200
Therefore substituting the value in the equation we get the frictional loss equal to 100 joules.
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