32. What is the concentration of hcoo- in an aqueous solution containing 10^-2M hcl and 10^-2M hcooh ? Ka of hcooh is 1.8*10^-4
Answer (1)
26th May, 2020
Hello!!!
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Given Ka of HCOOH = 1.8*10^-4
We know that,pKa = -log Ka
=-log 1.8*10^-4
=4*log 1.8
=4*0.25
pKa=1
ByHenderson Hasselbach equation,pH = pKa + log([A-]/[HA])
=pH of HCOOH = pKa of HCOOH + log([salt]/[acid])
=pH of HCOOH = 1+log([10^-2]/[10^-2])
therefore,,,pH of HCOOH =1
Concentration of HCOOH = 10^-pH
=10^-1
Hope it helps!!!!
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