4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block
of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3
. Find the total
elongation of the rod, taking into account its own weight. Take E = 210 GPa.

Question

4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block
of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3
. Find the total 
elongation of the rod, taking into account its own weight. Take E = 210 GPa.

Ayush · Accepted Answer

Hello Candidate,

The formula for Young's Modulus of Elasticity for steel is given by: Y= Mass Attached* Length/ Elongation* Area of Cross Section.

Here, the value of Young's Modulus=21000 Pascal, Mass Attached=100 kg, Length=3 metres, Area of Cross Section= 22/7*5*5 cm2= .0019 metres2. So, elongation= 1000*3/ .0019*21000= 75.18 metres.

Hope that this answer helps you.

Thank You.

Exams

Colleges

Predictors

Resources

Quick links

B.Tech CompanionUse Now Your one-stop Counselling package for JEE Main, JEE Advanced and BITSAT

Exams

Colleges & Courses

Predictors

Resources

Exams

Colleges

Predictors & E-Books

Resources

Engineering Preparation

Medical Preparation

Online Courses

Products

Exams

Colleges

Resources

Exams

Colleges

Predictors & Articles

Resources

Exams

Colleges

Predictors

Resources

NEET CompanionUse NowYour one-stop Counselling package for NEET, AIIMS and JIPMER

Exams

Colleges

Upcoming Events

Resources

Exams

Colleges

Resources

Quick Links

Top Streams

Specializations

Resources

Top Providers

Exams

Colleges

Resources

Diploma Colleges

Exams

Colleges

Resources

Exams

Resources

Top Courses & Careers

Colleges

Exams

Upcoming Events

Resources

Other Exams

Exams

Colleges

Top Countries

Student Visas

Exams

Top Schools

Products & Resources

NCERT Study Material

4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3 . Find the total elongation of the rod, taking into account its own weight. Take E = 210 GPa.

Related Questions

one end of a steel wire of length 0.2 m and radius 2×10^-3m is fixed.if the work done in twisting the free end of the wire is 3.85×10^-2J, calculate the angle through which the wire is twisted.Given rigidity modulus of steel wire=8.075×10^11Nm^2 Ans:1.58degree

a mass of 10 kg is suspended from the free end of spring when set for vertical oscillation the system executes 50 oscillation in 20 seconds calculate the force constant of the spring and angular frequency

A uniform chain of length 2m is kept on a free table such that a length of 60cm hangs freely from edge of the table the total mass of the chain is 4kg .what is the workdone in pulling the entire chain onto the table

if i get any course free seat if my neet score is 210

a mass of 10kg is suspended from the free end of a spring.when set for oscillations the system executes 100 oscillations in 5minute.calculate the force constant of the spring .

Trending Articles/News

Sign In/Sign Up

Download the Careers360 App on your Android phone

B.Tech CompanionUse Now
Your one-stop Counselling package for JEE Main, JEE Advanced and BITSAT

NEET CompanionUse Now
Your one-stop Counselling package for NEET, AIIMS and JIPMER