Question : 60 kg of alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is:
Option 1: 53 kg
Option 2: 44 kg
Option 3: 80 kg
Option 4: 24 kg
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Correct Answer: 44 kg
Solution :
Given:
Alloy A = 60 kg
Alloy B = 100 kg
Alloy A has lead and tin in the ratio of 3 : 2.
Alloy B has tin and copper in the ratio of 3 : 2.
According to the question statements,
In 60 kg of alloy A,
Tin = $\frac{2}{5}×60$ kg = 24 kg
In 100 kg of alloy B,
Tin = $\frac{1}{5}×100$ kg = 20 kg
$\therefore$ The amount of tin in the new alloy = 24 + 20 = 44 kg
Hence, the correct answer is 44 kg
.
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