64 identical drops each of capacity 5microF combine to form abig drop capacity of the big drop will be
Hi
The Capacitance of big drop will be 20μF
EXPLANATION
We have,
Volume of big drop = 64 times the volume of small drop
or 4/3 π.R3 =64 x 4/3 π.r3
Or R = 4r
Now, we know that the capacitance for a solid spherical body is directly proportion to radius of the solid sphere
Then,
Capacitance of big drop
= 4 x capacitance of small drop
=4 x 5
=20μF
Thank you