8 Views

Question : 80 litres of a mixture of alcohol and water contains 60% alcohol. If 'X' litres of water is added to this mixture, then the alcohol percentage in the new mixture becomes 40%. What is the value of 'X'?

Option 1: 20

Option 2: 80

Option 3: 40

Option 4: 60


Team Careers360 25th Jan, 2024
Answer (1)
Team Careers360 26th Jan, 2024

Correct Answer: 40


Solution : Given,
The mixture of alcohol and water = 80 litres
Initial alcohol concentration = 60%
Amount of alcohol in 80 litres of mixture = 60% of 80
= $\frac{60}{100}\times80$ = 48 litres
Also, 40 percent alcohol in the new mixture after the addition of X litres of water.
So, according to the question,
48 = $\frac{40}{100}$ × (80 + X)
⇒ 48 = $\frac{2}{5}$ (80 + X)
⇒ 240 = 2(80 + X)
⇒ 240 = 160 + 2X
⇒ 2X = 80
⇒ X = 40
Hence, the correct answer is 40.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books