Question : A 15 cm long perpendicular is drawn from the centre of a circle to its 40 cm long chord. Find the radius of the circle.
Option 1: 25 cm
Option 2: 27 cm
Option 3: 22 cm
Option 4: 20 cm
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Correct Answer: 25 cm
Solution : Given: Chord length = 40 cm The perpendicular distance from centre to chord = 15 cm Let the chord be AB and R be the radius of the circle. Since a perpendicular from the centre divides a chord into two equal parts, AP = 20 cm In $\triangle$OAP Using Pythagoras' theorem: OA2 = OP2 + PA2. R2 = 152 + 202 ⇒ R2 = 225 + 400 = 625 ⇒ R = 25 Hence, the correct answer is 25 cm.
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Question : In a circle, a 14 cm long chord is 24 cm from the centre of the circle. Find the length of the radius of the circle.
Option 1: 30 cm
Option 2: 25 cm
Option 3: 50 cm
Option 4: 27 cm
Question : A chord of length 40 cm is drawn in a circle having a diameter of 50 cm. What is the a minimum distance of another parallel chord of length 30 cm in the same circle from a 40 cm long chord?
Option 1: 10 cm
Option 2: 15 cm
Option 3: 5 cm
Question : Select the INCORRECT statement with respect to the properties of a circle.
Option 1: Two tangents drawn at the end of the diameter of a circle are parallel.
Option 2: The radius drawn perpendicular to a chord bisects the chord.
Option 3: The diameter of a circle is the longest chord of a circle.
Option 4: The perpendicular distance from the centre of a circle increases when the length of a chord increases.
Question : The length of the chord of a circle is 24 cm, and the perpendicular distance between the centre and the chord is 5 cm. The radius of the circle is:
Option 2: 13 cm
Option 3: 12 cm
Option 4: 24 cm
Question : The radius of a circle is 10 cm. The angle made by chord AB at the centre of this circle is 60°. What is the length of this chord?
Option 1: 40 cm
Option 2: 20 cm
Option 3: 30 cm
Option 4: 10 cm
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