Question : A 15 cm long perpendicular is drawn from the centre of a circle to its 40 cm long chord. Find the radius of the circle.
Option 1: 25 cm
Option 2: 27 cm
Option 3: 22 cm
Option 4: 20 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 25 cm
Solution : Given: Chord length = 40 cm The perpendicular distance from centre to chord = 15 cm Let the chord be AB and R be the radius of the circle. Since a perpendicular from the centre divides a chord into two equal parts, AP = 20 cm In $\triangle$OAP Using Pythagoras' theorem: OA 2 = OP 2 + PA 2 . R 2 = 15 2 + 20 2 ⇒ R 2 = 225 + 400 = 625 ⇒ R = 25 Hence, the correct answer is 25 cm.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : In a circle, a 14 cm long chord is 24 cm from the centre of the circle. Find the length of the radius of the circle.
Question : A chord of length 40 cm is drawn in a circle having a diameter of 50 cm. What is the a minimum distance of another parallel chord of length 30 cm in the same circle from a 40 cm long chord?
Question : If the length of a chord drawn at a distance of 21 cm from the centre of a circle is 40 cm, the radius (in cm) of the circle is:
Question : Select the INCORRECT statement with respect to the properties of a circle.
Question : The length of the chord of a circle is 24 cm, and the perpendicular distance between the centre and the chord is 5 cm. The radius of the circle is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile