A 500ml container has 15 ×10 ^12 molecules of an ideal gas. How many molecules will occupy 100ml at same temperature and pressure
PRACTICE MORE SUCH KINDS OF PROBLEMS SINCE THESE ARE DIRECTLY FORMULA BASED QUESTIONS AND U NEED TO STRENGTHEN THIS FIRST TO GET CAPABLE TO SOLVE MORE TRICKY QUESTIONS OF THE ENTRANCE EXAMS..
For the volume, , number of molecules,
Let there are number of molecules in the volume Since, the gas is given to be ideal gas, therefore it follows the ideal gas law, which is,
PV= NRT =NKT
where,
P = pressure of the gas.
V = volume of the gas.
T = absolute temperature of the gas.
R = Universal gas constant.
k = Boltzmann constant.
n = number of moles of the gas.
N = number of molecules of the gas.
We are given that the temperature and pressure of the gas is same.
Applying ideal gas law for the volume V1 ,
PV1 = N1KT
Applying ideal gas law for the volume V2,
PV2=N2KT
Dividing both these equations, we get,
PV1/PV2 = N1KT/N2KT
V1/V2 = N1/N2
Therefore, N2 = 100/500 * 15*10^12
= 3*10^12 molecules
