Question : A alone can do a piece of work in 7 days, while B alone can do it in 10 days. In how many days will they complete the same work if they both work together?
Option 1: $\frac{105}{17}$ days
Option 2: $\frac{35}{17}$ days
Option 3: $\frac{70}{17}$ days
Option 4: $\frac{84}{17}$ days
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{70}{17}$ days
Solution : One day work of A = $\frac{1}{7}$ One day work of B = $\frac{1}{10}$ One day work of A and B = $\frac{1}{7}+\frac{1}{10}$ = $\frac{10+7}{70}$ = $\frac{17}{70}$ Both A and B can complete the work in $\frac{70}{17}$ days. Hence, the correct answer is $\frac{70}{17}$ days.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : S alone can do a piece of work in 14 days. T alone can do the same work in 21 days. U alone can do the same work in 28 days. Working together, in how many days will they complete the work?
Question : Riya alone can complete a piece of work in 6 days while Siya alone can do the same work in 9 days. If they both work together, then how many days will be required to finish the work?
Question : A alone can complete a work in 16 days and B alone can complete the same work in 96 days. In how many days both A and B together can complete the same work?
Question : A can do a piece of work alone in 15 days, while B complete the same piece of work alone in 12 days. If they work on it together for 5 days, then the fraction of the work that will be left is:
Question : $\mathrm{N}_1$ alone can do 20% of a piece of work in 6 days, $\mathrm{N}_2$ alone can do 20% of the same work in 4 days, and $\mathrm{N}_3$ alone can do 50% of the same work in 12 days. In how many days can they complete the work, if all of them work together?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile