Question : A alone can make a table in 30 days while B alone can make it in 15 days. B started work alone and worked for 8 days. In how many days A alone can finish the remaining work?
Option 1: 14 days
Option 2: 10 days
Option 3: 12 days
Option 4: 15 days
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Correct Answer: 14 days
Solution :
Given,
A can make a table in 30 days.
B can make a table in 15 days.
B worked for 8 days.
Work done = Time × Work rate
⇒ Rate of A = $\frac{1}{30}$ table/day
⇒ Rate of B = $\frac{1}{15}$ table/day
⇒ Work done by B = Rate × Time = $\frac{1}{15} ×8 = \frac{8}{15}$ table
Remaining work = $1 - \frac{8}{15}=\frac{7}{15}$ table
So, the time taken by A to finish the remaining work $=\frac{\text{Work}}{\text{Rate}}=\frac{\frac{7}{15}}{\frac{1}{30}} = 14$ days
Hence, the correct answer is 14 days.
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