A and B start from point X towards Y and C from point Y towards X simultaneously at 9 am. If the ratio of speeds of A, B and C is 5:3:4 and A meets C at 10 am at what time will A, B and C reach their destination?
Answer (1)
16th Nov, 2020
Ratio of A:B:C speeds=5:3:4
A and C meet after 1 hour, so the total distance traveled by them equals to 5x.60+ 4x.60, where x is in metres per minute.
So the time taken by A to reach out the distance= distance/speed= (5x+4x).60/ 5x= 108 minutes. Time taken by B and C are in the ratios by 5/3 and 5/4 which means 180 minutes and 135 minutes respectively.
Hope that you have got your answer.
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