Question : A, B, and C are three angles of a triangle. If $A-B=45^{\circ}$ and $B-C=15^{\circ}$ then $\angle A=$?
Option 1: 83°
Option 2: 85°
Option 3: 95°
Option 4: 75°
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Correct Answer: 95°
Solution :
Given, $A-B=45^{\circ}$
And $B-C=15^{\circ}$
So, $A=45^{\circ}+B$
And, $C=B-15^{\circ}$
By the angle sum property of a triangle,
$A+B+C=180^\circ$
⇒ $45^{\circ}+B+B+B-15^{\circ}=180^{\circ}$
⇒ $3B+30^\circ = 180^\circ$
⇒ $B = 50^\circ$
Now, $A=45^{\circ}+B= 45^{\circ}+50^\circ= 95^\circ$
Hence, the correct answer is $95^\circ$
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