Question : A, B, and C are three points such that AB = 9 cm, BC = 11 cm, and AC = 20 cm. The number of circles passing through points A, B, and C is:
Option 1: 2
Option 2: 0
Option 3: 1
Option 4: 3
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 0
Solution : Given: A, B, and C are three points such that AB = 9 cm, BC = 11 cm, and AC = 20 cm. Here, AB + BC = 9 + 11 = 20 = AC So, no triangles can be formed using the given three sides. Therefore, no circle will pass through the given three points. Hence, the correct answer is 0.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If $\frac{a^{2} - bc}{a^{2}+bc}+\frac{b^{2}-ca}{b^{2}+ca}+\frac{c^{2}-ab}{c^{2}+ab}=1$, then the value of $\frac{a^{2}}{a^{2}+bc}+\frac{b^{2}}{b^{2}+ac}+\frac{c^{2}}{c^{2}+ab}$ is:
Question : $\triangle ABC$ is an isosceles triangle with AB = AC = 15 cm and an altitude from A to BC of 12 cm. The length of side BC is:
Question : A circle is inscribed in a ΔABC having sides AB = 16 cm, BC = 20 cm, and AC = 24 cm, and sides AB, BC, and AC touch circle at D, E, and F, respectively. The measure of AD is:
Question : In a $\triangle$ABC, DE||BC, D and E lie on AB and AC, respectively. If AB = 7 cm and BD = 3 cm, then find BC : DE.
Question : Let D and E be two points on the side BC of $\triangle ABC$ such that AD = AE and $\angle BAD = \angle EAC$. If AB=(3x+1) cm, BD = 9 cm, AC=34 cm and EC = (y + 1) cm, then the value of (x + y) is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile