Question : A, B, and C can separately complete a work in 12, 15, and 20 days, respectively. They worked together for 4 days. What will be the remaining work?
Option 1: $\frac{1}{2}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{8}$
Correct Answer: $\frac{1}{5}$
Solution :
Given: A, B, and C can separately complete a work in 12,15, and 20 days, respectively.
Efficiency of A = $\frac{1}{12}$
Efficiency of B = $\frac{1}{15}$
Efficiency of C = $\frac{1}{20}$
4 days work of A, B, and C = $4×(\frac{1}{12}+\frac{1}{15}+\frac{1}{20})=\frac{4}{5}$
Remaining work = $1–\frac{4}{5}=\frac{1}{5}$
Hence, the correct answer is $\frac{1}{5}$.
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