a bag contain 5red 4black balls a second bag contain 3red and 6black balls one of the two bag is selected random without replacement both of which are found to be red find the probability that these two balls are drawn from second bag
Answer (1)
29th Jan, 2022
Bag A=(4R+5B) balls
⇒ Bag B=(3R+6B) balls
⇒ Probability of red form bag A and black from bag B =
9
4
×
10
6
=
90
24
⇒ Probability of red from bag B and black from bag A =
10
3
×
9
5
=
90
15
⇒ P(balls of different colours)=P( red from bag A and black from bag B)+P( red from bag B and black from bag A)
=
90
26
+
90
15
=
90
41
All the best student,
Hope this helps you.
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