A ball falls from height 20 m if coefficient of restitution is 1 by 2 the time interval between starting point and second Bounce is
Answer (1)
12th Dec, 2018
Hi
As the height is proportional to aware of the velocity therefore the height after the first bounce would be one fourth that is 5m.
Now the time for first bounce sq(20/10 *2) that is 2s.
Now time for second bounce 2 * sq (1) that is 2s.
Therefore total time taken is equal to two plus two that is 4s.
Hope this helps
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